Answer:
300 i think
Step-by-step explanation:
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
Answer:
18
Step-by-step explanation:
Given the data:
180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg
The interquartile range (IQR) = Q3 - Q1
Reordering the data:
180, 188, 190, 192, 195, 200, 205, 209, 250
Q3 = 3/4(n+1)th term
Q3 = 3/4(10) = 7.5 th term = (205+209)/2 = 207
Q1 = 1/4(n+1)th term
Q1 = 1/4(10) = 2.5th term = (188+190)/2 = 189
Q3 - Q1 = 207 - 189 = 18
$=\sqrt{4^2}\times\sqrt{2^2\cdot3}$
$=4\times2\sqrt3=8\sqrt3$
Answer:
Step-by-step explanation:
From the given attachment to the question, the following can be deduced.
1. M is the midpoint of GH, given that M is the definition of midpoint.
2. GM ≅ MH, given that x = 2. So that,
GM = 5x = 5(2)
= 10
MH = 3x + 4 = 3(2) + 4
= 10
Thus, GM ≅ MH
3. GM = MH is the definition of congruence. This implies that they are similar.
4. 5x = 3x + 4, by substitution property of equality.
Since, x = 2 then;
5(2) = 3(2) + 4
10 - 10
5. 2x = 4, given that x = 2.
6. GH = GM + MH, by division property of equality.
