Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54
For b it is A,M and T
For C it is 0%
Answer:
Sides are x and x + 3.5 cm
Perimeter = 2(x + (x + 3.5))cm
4x +7 = 67
x = 15cm Answer
Step-by-step explanation:
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Answer
Multiply 648 by 3 to get for one week
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Answer:
15 nuts do not get found.
Step-by-step explanation:
Given that Of a squirrel's hidden nuts, for every 5 that get found, there are 3 that do not get found.
Total number of nuts squirrel had hidden = 40
Proportion of nuts not found to total = 3/(3+5) = 3/8
Hence out of 40, nuts not found =3/8(40) = 15 nuts.
15 nuts would not be found and 25 nuts would be found if squirrel had hidden in total 40 nuts.
This is because the proportion of found:unfound = 5:3
Hence 25:!5 =5:3 satisfies this
15 nuts are not found.