A. The cliff was 30.7 m high
B. I also got 9.5 as the horizontal distance
Here is my work, I find making charts like this one to find knowns and unknowns can be helpful
Here's what you need to know about waves:
Wavelength = (speed) / (frequency)
Now ... The question gives you the speed and the frequency,
but they're stated in unusual ways, with complicated numbers.
Frequency: How many each second ?
The thing that's making the waves is vibrating 47 times in 26.9 seconds.
Frequency = (47) / (46.9 s) = 1.747... per second. (1.747... Hz)
Speed: How far a point on a wave travels in 1 second.
The crest of one wave travels 4.16 meters in 13.7 seconds.
Speed = (4.16 m / 13.7 sec) = 0.304... m/s
Wavelength = (speed) / (frequency)
Wavelength = (0.304 m/s) / (1.747 Hz) = 0.174 meter per second
Answer is b that is Heat energy from below the ground converts water to steam to drive a steam turbine attached to an electrical generator.. .
Answer:
![x=(0.088m)\cos(\sqrt{\frac{k}{m} } t)](https://tex.z-dn.net/?f=x%3D%280.088m%29%5Ccos%28%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20%20t%29)
Explanation:
We first identify the elements of this simple harmonic motion:
The amplitude A is 8.8cm, because it's the maximum distance the mass can go away from the equilibrium point. In meters, it is equivalent to 0.088m.
The angular frequency ω can be calculated with the formula:
![\omega =\sqrt{\frac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%20%3D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D)
Where k is the spring constant and m is the mass of the particle.
Now, since the spring starts stretched at its maximum, the appropriate function to use is the positive cosine in the equation of simple harmonic motion:
![x=A\cos(\omega t)](https://tex.z-dn.net/?f=x%3DA%5Ccos%28%5Comega%20t%29)
Finally, the equation of the motion of the system is:
or
![x=(0.088m)\cos(\sqrt{\frac{k}{m} } t)](https://tex.z-dn.net/?f=x%3D%280.088m%29%5Ccos%28%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20%20t%29)