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tatyana61 [14]
2 years ago
6

A person walks 9 meters to the right and 8 meters to the left what's the distance and displacement​

Physics
2 answers:
nordsb [41]2 years ago
5 0
The distance is 17 and the displacement is 1
saw5 [17]2 years ago
4 0

Answer:

walked: 17 meters

displacement: 1

Explanation:

so you add 9+8 and the displacement is 1 b/c when you moved back those 8 meters you were still 1 meter away from where you where originally standing

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What is your operational definition for a fast reaction time?
LuckyWell [14K]

Answer:

The ability to react to a certain stimulus with a speedy and effective manner

Explanation:

7 0
3 years ago
Choose whether each of the following statements is true or false. In order to move a massive crate sitting on the floor, the for
velikii [3]

Answer:

 

Explanation:

1. False

The force you apply on crate is equal and opposite to the force that crate applies on you by Newton's third law of motion.

The force must over come the static frictional force between the crate and the  floor.

2. True

The object can move along another direction than the direction of net force. For example, when a car slows down, the net force is opposite to the direction of motion.

3. True

An object moving at constant velocity has zero net force acting on it.

4. False

An object at rest has forces acting on it but the summation of all the forces is zero i.e. the net force is zero.

6 0
3 years ago
Zad. 2 W marszobiegu chłopiec przebiegł 900 m w ciągu 205 min, a następnie przeszedł 300m w tym danym czasie. Jaka była średnia
USPshnik [31]

Odpowiedź:

0,049 m / s

Wyjaśnienie:

Biorąc pod uwagę, że:

Dystans biegu = 900m

Czas trwania = 205 minut

Długość przejścia = 300 m

Zajęty czas = 205 minut

Średnia prędkość :

(Przebieg + pokonany dystans) / całkowity czas

Średnia prędkość :

(900 m +. 300 m) / 205 + 205

1200 m / 410 minut

Minuty do sekund

1200 / (410 * 60)

1200/24600

= 0,0487804

= 0,049 m / s

8 0
3 years ago
What thrust does a 360 g model rocket need in order to have a vertical acceleration of 13.0 m/s2 on the earth?
maksim [4K]
Hope this helps u :)

5 0
3 years ago
A college student holds a pail full of water by the handle and whirls it around in a vertical circle at a constant speed. The ra
Pavlova-9 [17]

The minimum speed of the water must be 3.4 m/s

Explanation:

There are two forces acting on the water in the pail when it is at the top of its circular motion:

  • The force of gravity, mg, acting downward (where m is the mass of the water and g the acceleration of gravity)
  • The normal reaction, N also acting downward

Since the water is in circular motion, the net force must be equal to the centripetal force, so:

N+mg=m\frac{v^2}{r}

Where:

g=9.8 m/s^2

v is the speed of the pail

r = 1.2 m is the radius of the circle

The water starts to spill out when the normal reaction of the pail becomes zero:

N = 0

When this occurs, the equation becomes:

mg=m\frac{v^2}{r}\\v=\sqrt{gr}

And substitutin the values of g and r, we find the minimum speed that the water must have in order not to spill out:

v=\sqrt{(9.8)(1.2)}=3.4 m/s

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
3 years ago
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