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Katarina [22]
2 years ago
11

The field between two charged parallel plates is kept constant. If the two plates are brought closer together, the potential dif

ference between the two plates The field between two charged parallel plates is kept constant. If the two plates are brought closer together, the potential difference between the two plates _______.a. Increases. b. Decreases. c. Does not change.
Physics
1 answer:
Dovator [93]2 years ago
3 0
The answer is B, because it will lose potential energy.
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A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.24 m/s2 for 10.0 s. 2
valentina_108 [34]

Answer:

1817.448 m

Explanation:

Given:

Initial acceleration = 2.24 m/s²

Time for acceleration = 10 s

From  Newton's equation of motion

v = u + at

here v is the final velocity after the acceleration

v = 0 + 2.24 × 10 = 22.4 m/s

thus,

the displacement during acceleration

From  Newton's equation of motion

s_1=ut+\frac{1}{2}at^2

where,  

s is the distance

u is the initial speed = 0 m/s as starting from rest

a is the acceleration

t is the time

on substituting the respective values, we get

s_1=0\times10+\frac{1}{2}\times2.24\times10^2

or

s₁ = 112 m

for case 2

time = 1.25 minute = 1.25 × 60 = 75 seconds

displacement, s₂ = v × t = 22.4 × 75 = 1680 m

for the case 3

acceleration = - 9.86 m/s²

now,

the final velocity for the second case is the initial velocity for this case

thus,

s_3=22.4\times2.27+\frac{1}{2}(-9.86)\times2.27^2

or

s₃ = 50.848 - 25.40 = 25.448 m

hence,

the total displacement = s₁ + s₂ + s₃ = 112 m + 1680 m + 25.448 m

= 1817.448 m

3 0
3 years ago
Cumulus and cumulonimbus clouds are most likely to be formed by what
mote1985 [20]
They are formed by evaporation
5 0
3 years ago
Read 2 more answers
A car traveling at 30 m/s drives off a cliff that is 50 meters high? How far away does it land?
Semenov [28]

Answer:

The maximum range R_{max}= 132. 72 m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

                                R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }  m

Where,

                          g - acceleration due to gravity

Substituting the values in the above equation

                   R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }  

                                          = 132.72  m

Hence, the car lands at a distance, R_{max}= 132. 72 m            

3 0
3 years ago
a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
Katyanochek1 [597]
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
where F is force,
m is mass, and 
a is acceleration

Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

3 0
2 years ago
If you designed a rollercoaster, how might you design it? Would you have friction?
kvasek [131]
Yes, because you would need friction to slow down the rollercoaster to a stop. 
4 0
3 years ago
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