So this is asking the cube root of -27 then squared.
Cube root of -27=-3
And -3^2=9
So I believe your answer is 9
Answer:
D) y = -1/2x + 4
Step-by-step explanation:
Points on the graph: (0, 4) and (8, 0)
Slope:
m=(y2-y1)/(x2-x1)
m=(0 - 4)/(8-0)
m= -4/8
m = -1/2
Slope-intercept:
y - y1 = m(x - x1)
y - 4 = -1/2(x - 0)
y - 4 = -1/2x
y = -1/2x + 4
The answer is: [D]: " 2.6 " .
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Given: a = - 2.6 ; What is the value of "-a "?
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So, what is the value of " - (-2.6)" ?
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The opposite of a negative is a positive;
so, " - (-2.6) = 2.6 " ; which is: "Answer choice: [D] " .
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It would be 20 points bcuz it says each week it costs 20 points for unlimited bus rides
Answer:
(a) 0
(b) f(x) = g(x)
(c) See below.
Step-by-step explanation:
Given rational function:

<u>Part (a)</u>
Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

Substitute x = -1 to find the limit:

Therefore:

<u>Part (b)</u>
From part (a), we can see that the simplified function f(x) is the same as the given function g(x). Therefore, f(x) = g(x).
<u>Part (c)</u>
As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero). Therefore, the quotient approaches infinity.
