Answer:
In the total entropy of an isolated system, the thermal energy per unit temperature that is unavailable for doing useful work can never decrease.
I believe that the molar mass is 342.34g/mol
Answer:
G]ns^2np^5 group 17 (p-block)
G]ns^2np^2 group 14 (p-block)
G]ns^2mf^14 group 16 (f-block)
Explanation:
The outermost electronic configuration of an element shows the group to which it belongs in the periodic table as shown above in the answer. In addition, to that, we can be able to know from its electronic configuration, whether the element is a metal or not.
For instance;
G]ns^2mf^14 is a rare earth metal, G]ns^2np^2 group 14 is a metalloid while G]ns^2np^5 group 17 is a nonmetal.
Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value. The equation to describe the decay is
Nt=N0(1/2)

where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time. So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days
Answer:
91383 J
Explanation:
The equation of the reaction can be represented as:
------>
Given that:
The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.
The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.
= 
where:
= enthalpy of reaction
= the difference in the heat capacities of the products and the reactants.
∴
=

= ![1(91300 J.mol^{-1} ) +\int\limits^{435}_{298.15} [{(29.86)-\frac{1}{2}(29.38)-\frac{1}{2}29.13}]J.K^{-1}.mol^{-1} \, dT'](https://tex.z-dn.net/?f=1%2891300%20J.mol%5E%7B-1%7D%20%29%20%2B%5Cint%5Climits%5E%7B435%7D_%7B298.15%7D%20%5B%7B%2829.86%29-%5Cfrac%7B1%7D%7B2%7D%2829.38%29-%5Cfrac%7B1%7D%7B2%7D29.13%7D%5DJ.K%5E%7B-1%7D.mol%5E%7B-1%7D%20%5C%2C%20dT%27)
= 91300 J + (0.605 J.K⁻¹)(435-298.15)K
= 91382.79 J
≅ 91383 J