Answer : The value of
for
is
.
Solution : Given,
Solubility of
in water = 
The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.
The equilibrium equation is,

Initially - 0 0
At equilibrium - s s
The Solubility product will be equal to,
![K_{sp}=[Ba^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BBa%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)

![[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%3D%5BCO%5E%7B2-%7D_3%5D%3Ds%3D4.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL)
Now put all the given values in this expression, we get the value of solubility constant.

Therefore, the value of
for
is
.
<span>If the aqueous solution is 34% Licl then it is 100 - 34% water = 66%
From the calculation we've found out that it is 66% water. Then we need to find the weight from a 250 g solution.
66/100 * 250 = 165g
Hence it is 165g</span>