Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
y=2x+4
Step-by-step explanation:\solving for the slope you get (12-8)/(4-2)=4/2=2
solving for the y intercept you subtract 4 from 8 because 2*2 is 4 and (2,8) is 2 x values away from the y intercept so 8-4=4 so the y intercept is 4
so y=2x+4
A touchdown is scored 6 points for each touchdown and the points made after a touchdown is scored 2 points each. We are given the following variables:
t = number of touchdowns
p = number of points after a touchdown
Total score = 6t + 2p
Where 6 times t is the total score given by the number of touchdowns multiplied by 6 points, the same goes for the expression 2p.
Answer:
Step-by-step explanation:
4. 10x + 30 = 90
10x = 60
x = 6
complementary
5. 4x + 40 + 3x = 180
7x + 40 = 180
7x = 140
x = 20
supplementary
X≈2.48207399,<span>−<span>2.14874066</span></span>
