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3 years ago

9

you have $8.00 to make copies. each copy costs $0.40. write and solve an inequality that represents the number of copies you can

make?

1 answer:

Murrr4er [49]3 years ago

7 0

Answer:

0.40x $\leq \\$ 8

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If $a$, $b$, $c$, and $d$ are replaced by four distinct digits from $1$ to $9$, inclusive, then what's the largest possible valu

Alexxx [7]

Answer:

70

Step-by-step explanation:

for the value of difference to be largest, the minuend should be maximum(most possibly) and the subtrahend should be minimum

[in A-B=X, A is minuend and B is subtrahend ]

so, $a.b should be maximum. as there is a condition that 4 digits should be distinct, the product will be maximum if we choose 2 maximum valued numbers from the given numbers. so, one of them should be 9 and the other should be 8.

therefore, $a.b=9*8=72

as mentioned above, c.d$ should be minimum. this will be possible only when we choose 2 minimum valued numbers from the given numbers. so, one of them should be 1 and the other should be 2.

therefore, c.d$ = 1*2 = 2

hence, the difference = 72-2 = 70

thus, the largest possible value of the difference $a.b - c.d$ = 70

7 0

2 years ago

Please solve asap thanks

natima [27]

Answer:

6x+36=180

6x=144

x=24

Step-by-step explanation:

this is the correct answer

8 0

3 years ago

Read 2 more answers

A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that

ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 80.2, \sigma = 11$

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{63.7 - 80.2}{11}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

1 - 0.0668 = 0.9332

93.32% probability that a randomly selected score will be greater than 63.7.

5 0

3 years ago

Solve the equation by completing the sqaure. if necessary round to the nearest hundreth x^2+4x=1

viktelen [127]

Answer:

x = ± √ 5 − 2

Step-by-step explanation:

5 0

3 years ago

For one toss of a certain coin, the probability that the outcome is heads is 0.6. If this coin is tossed 5 times, which of the f

pishuonlain [190]

Answer:

The probability is 0.33696

Step-by-step explanation:

The probability that the outcome will be heads x times is calculated using the following equation:

$P(x) = nCx*p^{x} *(1-p)^{n-x}$

nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

This apply for variables that follows a binomial distribution. In which we have n independent and identical events with two possibles results: success and fail with a probability p and 1-p respectively.

So, In this case, n is equal to 5, and p is equal to 0.6 because we are going to call success the event in which the outcome of the coin is head.

Then, the probability that the outcome will be heads at least 4 times is calculated as:

P = P(4) + P(5)

Where P(4) is:

$P(4) = 5C4*0.6^{4} *(1-0.6)^{5-4}$

P(4)=0.2592

And P(5) is:

$P(5) = 5C5*0.6^{5} *(1-0.6)^{5-5}$

P(4)=0.07776

Finally, the probability is:

P = 0.2592 + 0.07776

P = 0.33696

5 0

3 years ago