Ask question

Ask question

All categories

VashaNatasha [74]

3 years ago

5

HELP ME PLEASE THANK YOU SO MUCHHHHHHHHHH

1 answer:

nikklg [1K]3 years ago

3 0

Answer:

1st and 3rd

Step-by-step explanation:

u welcome :)

You might be interested in

Don't know this please help me give brainly

Sergio039 [100]

Just pick random it’s helpful

6 0

3 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

How many sectors would be formed by a circle if each sector had a central angle of 30 degrees

Law Incorporation [45]

there are 360 degress in a circle if you cut a circle in half at its center aka its diameter the center angle would be 180 degree or a straight line 360/2 180 and a circle divide into 2 sectors so your questoin would be equal algebraically to 360x=30 360 is the totatal number degrees in every circle 30 is the resulting degree and x is the length of each of the sectors if you solve yo get 1/12 thus total sectors would be 12

6 0

3 years ago

The case of a rectangular electronic tablet has an area of A square inches. The length of the case is 12.5 in. Which equation re

Marizza181 [45]

Answer:

A/12.5=h

Step-by-step explanation:

A is 12.5 x h so you do inverse to work out height

3 0

3 years ago

Read 2 more answers

What is the remainder of the quantity 5 x cubed plus 7 x plus 5 end quantity divided by the quantity x plus 2 end quantity? Show

jarptica [38.1K]

The remainder of the polynomial equation is -49

<h3>What is a remainder of a polynomial equation?</h3>

The remainder of a quantity in an algebraic expression of a polynomial equation is the remaining amount of the quantity left and can not be divisible by the divisor.

From the given information, we are to find the remainder of the given algebraic equation:

$\mathbf{= \dfrac{5x^3+7x+5}{x+2} }$

Using the long division method, we have:

$\mathbf{= \dfrac{5x^3+7x+5}{x+2} } \implies \mathbf{5x^2 + \dfrac{-10x^2+7x+5}{x+2}}$

Divide by $\mathbf{ \dfrac{-10x^2+7x+5}{x+2}}$ , we have:

$\mathbf{= 5x^2- 10x+ \dfrac{27x+5}{x+2}}$

Divide by $\mathbf{\dfrac{27x+5}{x+2}}$ , we have:

$\mathbf{= 5x^2- 10x+ 27 +\dfrac{-49}{x+2}}$

Learn more about finding the remainder of a polynomial equation here:

brainly.com/question/24978997

#SPJ1

4 0

1 year ago