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netineya [11]
3 years ago
9

Which statement best describes the change in an objects momentum if the net force acting on the object is greatly increased ?

Physics
2 answers:
natta225 [31]3 years ago
4 0

<u>Answer:</u>

<em>The object’s momentum will greatly increase if the net force acting on the object is greatly increased. So option C is the best statement which describes the change in object momentum.</em>

<u>Explanation:</u>

So as the force is directly proportional to momentum and it is obtained by performing the first order derivation of momentum, the variation in force and momentum will have to be same.

F = \frac{MomentumChange}{time}

The force being the derivative of momentum indicates that if the net force acting on object is greatly increased means the momentum will also be undergoing great increase as the acceleration of the object will also be increased greatly due to increase of force.

garri49 [273]3 years ago
3 0

Answer:

Answer C : The object's momentum will greatly increase

Explanation:

Recall that force and linear momentum are closely related by the equation:

F = \frac{MomentumChange}{time}

Both, Momentum Change and Force (F) are in the numerator of on either side of the equation, so they are in direct proportionality. A large force (force greatly increased) will be the reflection of a large change in momentum.

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A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it w
choli [55]

The equation relevant to this is:

S(t) = So + Vot - At²/2 <span>

</span>

<span>Therefore we can create two equations:
<span>S(t) = 90 = So - 4t - 16.1t²                                      --> eqtn  1</span>
<span>S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)²                     --> eqtn 2</span>

</span>

<span>Expanding eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4) 
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4 
10 + 8 + 64.4 = So - 68.4t - 16.1t² 
<span>82.4 = So - 68.4t - 16.1t²                                        --> eqtn 3</span></span>

 <span>
Subtracting eqtn 1 by eqtn 3:</span>

 90 = So - 4t - 16.1t² 

82.4 = So - 68.4t - 16.1t²

 

=> 7.6 = 64.4t

t = 0.118 s

 

Therefore calculating for initial height So:<span>

<span>82.4 = So - 68.4(0.118) - 16.1(0.118)²

<span>So = 90.7 ft</span></span></span>

7 0
3 years ago
A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?
Blababa [14]

Answer:

Explanation:

V^2=V^2_o+2a(x_f-x_i)

28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2

5 0
3 years ago
When an object is fully converted into energy the amount of energy liberated is
EleoNora [17]

Answer:

Mass, m = 4 kg

Explanation:

<u>Given the following data;</u>

Energy = 3.6 * 10^17 Joules

We know that the speed of light is equal to 3 * 10⁸ m/s.

To find the mass of the substance;

The theory of special relativity by Albert Einstein gave birth to one of the most famous equation in science.

The equation illustrates, energy equals mass multiplied by the square of the speed of light.

Mathematically, the theory of special relativity is given by the formula;

E = mc^{2}

Where;

  • E is the energy possessed by a substance.
  • m is the mass.
  • c is the speed of light.

Substituting into the formula, we have;

3.6 * 10^{17} = m * 300000000^{2}

3.6 * 10^{17} = m * 9*10^{16}

m = \frac {3.6 * 10^{17}}{9*10^{16}}

Mass, m = 4 kg

8 0
3 years ago
3
german

Answer:

The time taken by the ship to cover the distance, t = (x/25)  s

Explanation:

Given data,

The initial velocity of the ship, u = 20 m/s

The final velocity of the ship, v = 30 m/s

The average velocity of the ship, V = (20 + 30)/ 2

                                                           = 25 m/s

The distance covered by the ship, d = x m

Then the time taken by the ship to cover the displacement is,

                   d =  V x t

∴                   t = d / V

Substituting the values,

                     t = x / 25

                     t = (x/25)  s

Hence, the time taken by the ship to cover the distance, t = (x/25) s

4 0
3 years ago
Calculate the momentum of a 2500kg car with a velocity of 20 m/s​
Sedaia [141]

Answer:

50000 kg.m/s

Explanation:

p = mv

p = 2500 × 20

p = 50000 kg. m/s

6 0
4 years ago
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