The equation relevant to this is:
S(t) = So + Vot - At²/2 <span>
</span>
<span>Therefore
we can create two equations:
<span>S(t) = 90 = So - 4t - 16.1t² -->
eqtn 1</span>
<span>S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)² --> eqtn 2</span>
</span>
<span>Expanding
eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4)
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4
10 + 8 + 64.4 = So - 68.4t - 16.1t²
<span>82.4 = So - 68.4t - 16.1t² -->
eqtn 3</span></span>
<span>
Subtracting eqtn 1 by eqtn 3:</span>
90 = So - 4t - 16.1t²
82.4 = So - 68.4t - 16.1t²
=> 7.6 = 64.4t
t = 0.118 s
Therefore calculating for initial height So:<span>
<span>82.4 = So - 68.4(0.118) - 16.1(0.118)²
<span>So = 90.7 ft</span></span></span>
Answer:
Mass, m = 4 kg
Explanation:
<u>Given the following data;</u>
Energy = 3.6 * 10^17 Joules
We know that the speed of light is equal to 3 * 10⁸ m/s.
To find the mass of the substance;
The theory of special relativity by Albert Einstein gave birth to one of the most famous equation in science.
The equation illustrates, energy equals mass multiplied by the square of the speed of light.
Mathematically, the theory of special relativity is given by the formula;

Where;
- E is the energy possessed by a substance.
- m is the mass.
- c is the speed of light.
Substituting into the formula, we have;



Mass, m = 4 kg
Answer:
The time taken by the ship to cover the distance, t = (x/25) s
Explanation:
Given data,
The initial velocity of the ship, u = 20 m/s
The final velocity of the ship, v = 30 m/s
The average velocity of the ship, V = (20 + 30)/ 2
= 25 m/s
The distance covered by the ship, d = x m
Then the time taken by the ship to cover the displacement is,
d = V x t
∴ t = d / V
Substituting the values,
t = x / 25
t = (x/25) s
Hence, the time taken by the ship to cover the distance, t = (x/25) s