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2 years ago

Which statement best describes the change in an objects momentum if the net force acting on the object is greatly increased ?

Physics

2 answers:

natta225 [31]2 years ago

4 0

Answer:

The object’s momentum will greatly increase if the net force acting on the object is greatly increased. So option C is the best statement which describes the change in object momentum.

Explanation:

So as the force is directly proportional to momentum and it is obtained by performing the first order derivation of momentum, the variation in force and momentum will have to be same.

$F = \frac{MomentumChange}{time}$

The force being the derivative of momentum indicates that if the net force acting on object is greatly increased means the momentum will also be undergoing great increase as the acceleration of the object will also be increased greatly due to increase of force.

garri49 [273]2 years ago

3 0

Answer:

Answer C : The object's momentum will greatly increase

Explanation:

Recall that force and linear momentum are closely related by the equation:

$F = \frac{MomentumChange}{time}$

Both, Momentum Change and Force (F) are in the numerator of on either side of the equation, so they are in direct proportionality. A large force (force greatly increased) will be the reflection of a large change in momentum.

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Montano1993 [528]

Answer:

Speed of the speeder will be 28 m/sec

Explanation:

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We can change 90 km/hr in m/sec

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3 years ago

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If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d

Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

$v_{i}=-44.5m/s\\v_{f}=55.5m/s$

Now we need to find the initial momentum

$P_{1}=m*v_{i}$

Substitute the given values

$P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s$

Now for final momentum

$P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s$

So the change in momentum is given as:

ΔP=P₂-P₁

$=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s$

ΔP=20 kg.m/s

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Answer:

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