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netineya [11]
3 years ago
9

Which statement best describes the change in an objects momentum if the net force acting on the object is greatly increased ?

Physics
2 answers:
natta225 [31]3 years ago
4 0

<u>Answer:</u>

<em>The object’s momentum will greatly increase if the net force acting on the object is greatly increased. So option C is the best statement which describes the change in object momentum.</em>

<u>Explanation:</u>

So as the force is directly proportional to momentum and it is obtained by performing the first order derivation of momentum, the variation in force and momentum will have to be same.

F = \frac{MomentumChange}{time}

The force being the derivative of momentum indicates that if the net force acting on object is greatly increased means the momentum will also be undergoing great increase as the acceleration of the object will also be increased greatly due to increase of force.

garri49 [273]3 years ago
3 0

Answer:

Answer C : The object's momentum will greatly increase

Explanation:

Recall that force and linear momentum are closely related by the equation:

F = \frac{MomentumChange}{time}

Both, Momentum Change and Force (F) are in the numerator of on either side of the equation, so they are in direct proportionality. A large force (force greatly increased) will be the reflection of a large change in momentum.

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Answer:

B.  It has increased the chili's potential energy

Explanation:

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So, if the chili has cooled after 10 minutes, it has increased the potential energy of the substance.

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4 years ago
A girl walks 5km due north,then in the direction of 60° of northeast towards her final destination.If the magnitude of her resul
storchak [24]

Answer:

4.2 km

Explanation:

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Let the starting point be A, hence the side opposite to the  angle = a = distance travelled in north east direction.

Let the point of 60° of northeast be B = 90° + (90° - 60°) = 120°, hence the side opposite to the  angle = b = resultant displacement = 8 km.

Let C be the endpoint, hence the side opposite to the  angle = c = distance travelled north = 5 km

Using sine rule:

\frac{b}{sin(B)}=\frac{c}{sin(C)}  \\\\\frac{8}{sin(120)}=\frac{5}{sin(C)}  \\\\sin(C)=\frac{5*sin(120)}{8} =0.5412\\\\C=sin^{-1}(0.5412)=32.8^o\\\\

∠A + ∠B + ∠C = 180° (sum of angle in a triangle)

∠A + 120 + 32.8 = 180

∠A = 27.2°

\frac{b}{sin(B)}=\frac{a}{sin(A)}  \\\\\frac{8}{sin(120)}=\frac{a}{sin(27.2)}  \\\\a=\frac{8*sin(27.2)}{sin(120)} \\\\a=4.2\ km

Therefore she travelled 4.2 km in the north east direction

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e and b

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Answer:

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