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JulsSmile [24]
3 years ago
9

ANYONE HELP ME PLEASE!

Physics
1 answer:
DedPeter [7]3 years ago
7 0

Answer:

Kinetic energy is the energy in moving objects or mass. Examples include mechanical energy , electrical energy etc.

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blagie [28]

Answer:

The second one

4 0
3 years ago
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Importance of electric circuit​
Feliz [49]

Answer:

It is important because it carries useful energy through your house that you can use for a variety of tasks.

Explanation:

Hope this helped !

8 0
3 years ago
An electric field of intensity 4.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
Anestetic [448]

Answer:

Electric flux will be equal to 1041.25Nm^2/C

Explanation:

We have given electric field E=4.25KN/C=4.25\times 10^3N/C=4250N/C

Sides of rectangle is given as 0.350 m wide and 0.700 m long

So length of rectangle l = 0.7 m and width w = 0.35 m

So area of rectangle A=0.7\times 0.35=0.245m^2

It is given that electric field is along the x axis

So angle between plane and electric filed \Theta =0^{\circ}

So electric flux will be equal to \Phi =EAcos\Theta =4250\times 0.245\times cos0^{\circ}=1041.25Nm^2/C

5 0
3 years ago
A horizontal spring with stiffness 0.5 N/m has a relaxed length of 19 cm (0.19 m). A mass of 22 grams (0.022 kg) is attached and
lawyer [7]

Answer:

 v = 0.0147 m / s

Explanation:

For this exercise let's use energy conservation

Starting point. Fully stretched spring

            Em₀ = Ke = ½ k (x-x₀)²

Final point. Unstretched position

          Emf = K = ½ m v²

          Emo = Emf

         ½ k (x- x₀)² = ½ m v²

           v = √m/k    (x-x₀)

Let's calculate

            v = √(0.022 / 0.5)      (0.26-0.19)

            v = 0.0147 m / s

6 0
3 years ago
An object has a mass of 60 kg. It decelerates from 50 m/s to 20 m/s when a resultant force of 300 N acts on it. For how long doe
Pavlova-9 [17]
  • Force=300N
  • Mass=60kg

Find Acceleration

\\ \rm\longmapsto F=ma

\\ \rm\longmapsto a=\dfrac{F}{m}

\\ \rm\longmapsto a=\dfrac{-300}{60}

\\ \rm\longmapsto a=-5m/s^2

Now

  • u=50m/s
  • v=20m/s

Using 1st equation of kinematics

\\ \rm\longmapsto v=u+at

\\ \rm\longmapsto t=\dfrac{v-u}{a}

\\ \rm\longmapsto t=\dfrac{20-50}{-5}

\\ \rm\longmapsto t=\dfrac{-30}{-5}

\\ \rm\longmapsto t=6

4 0
3 years ago
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