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kvv77 [185]
3 years ago
14

Jack is making a table to summarize his notes about the different types of scientific investigations. He places an X into the bo

x that has the steps included in the investigation. Part of the table is shown.
Where should Jack place an X for the investigations in the table?

in Box 1
in Box 2
in Box 3
in Box 4
Physics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0
Is this all the information ??
Helen [10]3 years ago
5 0

Answer:

The answer is Box 1

Explanation:

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a runner goes from 5 m/s to a stop in 10 seconds. Calculate his acceleration. Show your work and include units. ​
AnnyKZ [126]
Hope this helps you out

5 0
3 years ago
Which of the following is an example of frontier research?
riadik2000 [5.3K]

Testing the electrical resistance of different materials. it is the answer

3 0
3 years ago
Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente
yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

v=\lambda f  (1)

v: speed of the wave = 1,97 m/s

λ: wavelength

f: frequency of the wave = 0,07 Hz

You replace the values of v and f in the equation (1) and solve for λ:

\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m

hence, the wavelength of the wave is 28,14 m

5 0
3 years ago
Suppose you find yourself in your friend's third floor apartment building when you smell smoke coming from outside the door. you
Alborosie

(a) Because the tension in the rope would be larger than the maximum value allowed

When you are sliding down the slope, there are two forces acting on you:

- Your weight, W=mg, acting downward, where

m = 70 kg is your mass

g = 9.8 m/s^2 is the acceleration of gravity

- The tension in the rope, T, acting upward

Therefore, the equation of motion is

T-mg=ma

where a is the acceleration.

If you want to slide at constant speed, then the acceleration must be zero:

a = 0

And so the equation becomes

T-mg=0

This means that the tension in the rope must be:

T=mg=(70 kg)(9.8 m/s^2)=686 N

Which is larger than the maximum tension allowed in the rope (500 N), so the rope will break.

(b) 2.66 m/s^2 downward

Again, we must refer to the equation of the forces:

T-mg=ma

In this case, we want the tension in the rope to be the maximum allowed value,

T = 500 N

the other data are

m = 70 kg is your mass

g = 9.8 m/s^2 is the acceleration of gravity

Substituting into the equation, we can find the corresponding value of acceleration:

a=\frac{T-mg}{m}=\frac{500-(70)(9.8)}{70}=-2.66 m/s^2

where the negative sign means the acceleration is downward.

8 0
4 years ago
If a 1.00 kg body has an acceleration of 2.44 m/s2 at 53° to the positive direction of the x axis, then what are (a) the x comp
Ilia_Sergeevich [38]

(a) Fx = 1.464 N

(b) Fy = 1.952 N

(c) F(x, y) = 1.464 i + 1.952 j

Given

Mass = 1kg

Acceleration = 2.44 m/s2

Angle with positive X axis = 53°

As we know

F = ma

By substituting value

F= 1×2.44 N

F= 2.44 N

(a)   Component of force in X direction

Fx = F Cosθ

Fx = 2.44 Cos(53°)

Fx = 2.44 × 0.60 = 1.464 N

(b) Component of force in Y direction

Fy = F Sinθ

Fy = 2.44 Sin(53°) = 2.44 × 0.80 = 1.952 N

(c) Net force in vector notation

F(x, y) = 1.464 i + 1.952 j

Thus we got net force.

#SPJ4

For details visit www.brainly.com

6 0
2 years ago
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