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Sedbober [7]
4 years ago
7

Does specific heat change with mass?

Physics
1 answer:
ch4aika [34]4 years ago
7 0
Heat<span> capacity ( C ) </span>does change with mass<span>. However, </span>specific heat<span> is the </span>heat<span>capacity per unit </span>mass<span> ( c=Cm ). Therefore if you double the amount of </span>mass<span> in your system, you've doubled its </span>heat<span> capacity, but you've kept the </span>specific heat<span> the same. ... </span>Specific<span> gravity is another such quantity.</span>
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The weight of a body floating in a liquid is​
djverab [1.8K]

Answer:

The apparent weight is the weight of the body minus the weight of the liquid displaced. The body will float only when both the weights are same. In this case, the given body of weight W is floating and hence the apparent weight is zero.

4 0
3 years ago
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The Doppler effect is the apparent change in frequency due to the movement of the source and the observer. This means an object
Alekssandra [29.7K]

Answer:

Doppler effect changes the wavelength of the light emitted, depending upon whether source is moving away or coming towards the observer(detector).

Explanation:

Doppler effect in light is actually a relativistic effect but somewhat similar to the one which happens in sound waves.

When the source is moving away from the detector, the wavelength of the light emitted from the source appears to be increased as seen by the detector, as a result the frequency decreases(we know that frequency of light= speed of light/wavelength of light. Here speed of light is constant and frequency of light is inversely proportional to its wavelength)

Due to this decrease in frequency the light emitted from the source appears more red, since red color is on low frequency side in the electromagnetic spectrum.

Similarly for the source moving towards the detector, the wavelength appears to be decreased, thereby resulting in increase in frequency and the source appears blue. The shift in frequency is known as doppler shift.

The shift in frequency when the source is moving away is known as redshift and the one where the source is moving towards detector is known as blueshift

4 0
3 years ago
Why is Joshuas head so big?
otez555 [7]

Answer:

because he has a big brain and skull

Explanation:

well technically the bigger brain the bigger the head because the size of your skull determines the size of the brain so that concludes why Joshua's head is so big.

<h2>hope this helps</h2>
4 0
3 years ago
A 6500 kg satellite orbits a planet. If its distance to the center of the planet is 9e6 m and its speed is 6.7e3 m/s, what is th
Ira Lisetskai [31]

Answer:

the gravitational force between the satellite and the planet is 32.4  * 10³N

Explanation:

It is given that,

Mass of the satellite, m = 6500 kg

Speed of the satellite, v = 6.7 × 10³ m/s

distance to the center of the planet = 9  × 10⁶m

Let F is the magnitude of the gravitational force exerted on the satellite by the planet. The centripetal force is equal to the gravitational force. It is equal to :

F = \frac{mv^2}{R}

F = \frac{6500  \times (6.7 * 10^3)}{9 * 10^6}

= 32.4  * 10³N

the gravitational force between the satellite and the planet is 32.4  * 10³N

3 0
3 years ago
Read 2 more answers
An emf source with emf of 200 V, a resistor with R =50.0 Ω, and a capacitor with C = 4.0 mF are connected in series. As the capa
Gemiola [76]

Answer:

0.6 C

Explanation:

From the question,

Since the Resistor and the capacitor are connected in series.

The voltage across the resistor + Voltage across the capacitor = Total voltage.

Vt = Vr+Vc............... Equation 1

Where Vt = Total voltage, Vr = Voltage across the resistor, Vc = Voltage across the capacitor

make Vc the subject of the equation

Vc = Vt-Vr.............. Equation 2

From ohm's law,

Vr = IR................... equation 3

Where I = current, R = Resistance.

Given: I = 1 A, R = 50 Ω

Substitute into equation 3

Vr = 1(50)

Vr = 50 V

Also given: Vt = 200 V

Substitute into equation 2

Vc = 200-50

Vc = 150 V.

Applying,

Q = CVc..................... Equation 4

Where Q = charge on each plate of the capacitor, C = Capacitance of the capacitor

Given: C = 4.0 mF = 4.0×10⁻³ F, Vc = 150 V

Substitute into equation 4

Q = 4.0×10⁻³(150)

Q = 0.6 C

5 0
3 years ago
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