Answer: 0.067 s
Explanation:s = Ut + 1/2at^2
0.6 = 9t + 0.5 *10 *t^2
Where a = g =10m/s/s
Solving the quadratic equation
5t^2 + 9t - 0.6=0,
t= 0.067 s and - 1.7 s
Of which 0.067 s is a valid time
Work is force times distance. If there's no distance, there's no work being done.
The option is Work.
The product of charge and potential is equal to the energy. Adn, as we know work is related to energy as the capacity to do work.
Alos, because, Potential is given as, V = E/q
or E = Vq
Thus, t<span>he product of charge through, and potential across, an electrical device is:work
</span>
Answer:
0.37 m
Explanation:
The angular frequency, ω, of a loaded spring is related to the period, T, by

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

A is the amplitude or maximum displacement from the equilibrium.

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

is the final velocity,
is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

