Convert 4.500000000 to scientific notation

5. Can you determine the number of neutrons in the nucleus of an atom by looking at the element's average atomic mass and the at

Shkiper50 [21]

Answer:

No you can't

Explanation:

The atomic number is the amount of protons in element's nucleus, that's one reason why. The second reason is that the atomic mass is protons and neutrons combined, their estimated value, which doesn't show how much neutrons are in an element. It does show combined, but not specifically neutrons

7 0

3 years ago

Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin

STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of $KI$ and $AgNO_3$ .

$\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}$

Molar mass of KI = 166 g/mole

$\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole$

and,

$\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole$

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

$KI+AgNO_3\rightarrow KNO_3+AgI$

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of $AgNO_3$

So, 0.0178 mole of KI react with 0.0178 mole of $AgNO_3$

From this we conclude that, $AgNO_3$ is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgI$

From the reaction, we conclude that

As, 1 mole of $KI$ react to give 1 mole of $AgI$

So, 0.0178 moles of $KI$ react to give 0.0178 moles of $AgI$

Thus,

Moles of AgI = Moles of $I^-$ anion = Moles of $Ag^+$ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

$\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}$

$\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M$

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0

3 years ago

The theoretical yield of 1,2-epoxycyclohexane is _______________ grams, when starting with 3.0 grams of trans-2-bromocyclohexano

Amanda [17]

Answer:

1.64g

Explanation:

The reaction scheme is given as;

2-bromocyclohexanol --> 1,2-epoxycyclohexane + HBr

From the reaction above,

1 mol of 2-bromocyclohexanol produces 1 mol of 1,2-epoxycyclohexane

3.0 grams of trans-2-bromocyclohexanol.

Molar mass = 179.05 g/mol

Number of moles = mass / molar mass = 3 / 179.05 = 0.016755 mol

This means 0.016755 mol of 1,2-epoxycyclohexane would be produced.

Molar mass = 98.143 g/mol

Theoretical yield = Number of moles * Molar mass

Theoretical yield = 0.016755 * 98.143 ≈ 1.64g

7 0

3 years ago

calculate the charge on plates if the plate area is 100 cm2 , the gap between plates is 10 mm and the scale is reading 1.0 gram.

Law Incorporation [45]

Answer: The charge on the plates are 88.4 picafarad

Explanation:The equation used in measuring charge in a plate is given as:

C=Q/V =E A/D

Where E= dielectric content

A= Area of plates

d= distance between plates

Using dielectric constant for Air=8.84×10-12F/m

A=100cm2=0.01m2

d=10mm=0.001m

C= 8.84×10-12×0.01/0.001

C= 88.4 picafarad

8 0

3 years ago

Which mix will be homogeneous?

DIA [1.3K]

Answer:

B

Explanation:

food coloring and water are inseparable after mixed.

4 0

3 years ago

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