Question

Suppose there is 1. 00 l of an aqueous buffer containing 60. 0 mmol of acetic acid (pa=4. 76) and 40. 0 mmol of acetate. Calculate the ph of this buffer.

Answer 1

For 1. 00 l of an aqueous buffer containing 60. 0 mmol of acetic acid (pa=4. 76) and 40. 0 mmol of acetate, the pH of this buffer is 4.58.

What is handerson Hasselbalch equation?

It is expressed as:

pH = pKa + log [A-]/[HA]

where,

[A-] is the molar concentration of conjugate base

[HA] is the molar concentration of weak acid

Given,

pKa = 4.76

Calculation of concentration:

• For acetic acid

C = n/V

= 60/1000

= 0.06M

• For acetate

C = 40/1000

= 0.04M

Now, substituting values in equation we get,

pH = 4.76 + log(0.04/0.06)

pH = 4.76 + (-0.176)

pH = 4.58

Thus by using Henderson Hasselbalch equation we find the value of pH of the buffer is 4.58.

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