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3 years ago

4. A yellow cab Taxi charges $5.00 flat rate in addition of $0.65 per mile. Jan has no more than $20 to spend on a ride.

Mathematics

1 answer:

gogolik [260]3 years ago

6 0

Answer:

$5+0.65x\le 20$

Step-by-step explanation:

Let x be the number of miles Jan can drive in a taxi.

The cost of this ride consists of

$5.00 flat rate
$.065 per mile

So, per x miles Jan will pay $0.65x and the total cost of the ride will be

$5.00+$0.65x

Jan has no more than $20 to spend on a ride, then the total cost of his ride must be less or equal to $20. Mathematically, you can write this as

$5+0.65x\le 20$

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1760/ 20 = 88
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3 years ago

z varies directly with x^2 and inversely with y. When x = 2 and y = 4, z = 3. What is the value of z when x = 4 and y = 9?

Aloiza [94]

Attached the solution and work.

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3 years ago

Conjunction and disconjuction

maks197457 [2]

Step-by-step explanation:

When two statements are connected with an 'and,' you have a conjunction.

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2 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

3 years ago

PLEASE HELP

enot [183]

Answer:18.9 miles

1 inch=5.4

3.5 inches =3.5×5.4

=18.9miles

hope this helps

please like and mark as brainliest

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3 years ago