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olya-2409 [2.1K]
3 years ago
8

Use the table to answer the question.

Mathematics
2 answers:
Delvig [45]3 years ago
8 0
The answer is 3.45 (C) because 1.15 x 3 = 3.45
andrezito [222]3 years ago
7 0
It will cost 3.45 because you X 1.15 by 3
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Help me to do this question plz <br>I will make you as brainlist ​
romanna [79]

Answer:

I don't understand the language but I can do it

6 0
3 years ago
Find the area of the triangle formed by the origin and the points of intersection of parabolas y=− 1/3 (x−1)^2+8 and y=x^2−2x−3.
Kobotan [32]

Answer:

The area of the triangle formed by origin, and the points (4,5) and (-2,5) will be 15 sq. units.

Step-by-step explanation:

The two parabolas are y = - \frac{1}{3}(x - 1)^{2} + 8 and y = x² - 2x - 3.

Now, solving those two equations we will get the points of intersection.

So, - \frac{1}{3}(x - 1)^{2} + 8 = x^{2} - 2x - 3

⇒ - (x - 1)² + 24 = 3x² - 6x - 9

⇒ -x² + 2x - 1 + 24 = 3x² - 6x - 9

⇒ 4x² - 8x - 32 = 0

⇒ x² - 2x - 8 = 0

⇒ x² - 4x + 2x - 8 = 0

⇒ (x - 4)(x + 2) = 0

So, x = 4 or - 2.

Now, for x = 4 , y = 4² - 2(4) - 3 = 5 and the point of intersection is (4,5).

Or, for x = - 2, y = (- 2)² - 2(- 2) - 3 = 5 and the point of intersection is (-2,5).

Now, points (4,5) and (-2,5) make a straight line parallel to the x-axis at a perpendicular distance of 5 units from origin and its length is (4 - (- 2)) = 6 units.

So, the area of the triangle formed by origin, and the points (4,5) and (-2,5) will be = 0.5 × 5 × 6 = 15 sq. units. (Answer)

8 0
3 years ago
K/w = v-w , for x indicated variable
brilliants [131]

Answer:

x=k/v-w

Step-by-step explanation:

The first w I'm guessing you meant the x? Hope this helped!

6 0
4 years ago
How do you solve this system: y= -3/2x, and 3x+2y=-4 by substitution?
Soloha48 [4]
Download Photomath it will answer it with step by step work
4 0
3 years ago
Read 2 more answers
Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)​
Mrrafil [7]

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Step-by-step explanation:

Given polynomials are:

(x^3+3x^2+1)\\and\\(3x^2+6x-2)

In order to multiply both polynomials, we will use the distributive property

So,

= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2

Combining like terms

=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2

Hence,

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Keywords: Polynomials, variables

Learn more about polynomials at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

6 0
4 years ago
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