The property above is distribution property where we distribute x-term in the function.
Substitute both f(x) and g(x) in.
Évaluate/Combine like terms.
The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)
<u>Alternative</u>
<u>Answer</u>
Both answers work. The second answer is in factored form.
Let me know if you have any doubts!
x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)
Now, factoring the term:
The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation, the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,
So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
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