Answer:
Microphones are used in many applications such as telephones, hearing aids, public address systems for concert halls and public events, motion picture production, live and recorded audio engineering, sound recording, two-way radios, megaphones, radio and television broadcasting.
Answer:
it was equal to the weight of the object
hope it helped ☺️
Answer:
A. 16 J
B. 16 J
C. 8 N
Explanation:
A. Determination of the kinetic energy.
Mass (m) = 0.5 Kg
Velocity (v) =. 8 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 0.5 × 8²
KE = ½ × 0.5 × 64
KE = 0.5 × 32
KE = 16 J
B. Determination of the Workdone by the force.
Kinetic energy (KE) = 16 J
Workdone =.?
Workdone and kinetic energy has the same unit of measurement. Thus,
Workdone = kinetic energy
Workdone = 16 J
C. Determination of the force.
Workdone (Wd) = 16 J
Displacement (s) = 2 m
Force (F) =?
Wd = F × s
16 = F × 2
Divide both side by 2
F = 16 / 2
F = 8 N
Answer:ω = 100000rev/min * 2πrad/rev * 1min/60s = 10 500 rad/s
t = 2 min = 120 s
(a) ω = ωo + at
10500 rad/s = 0rad/s + α*120s
α = 87.3 rad/s²
(b) a_t = αr = 87.3rad/s² * 0.095m = 8.29 m/s²
(c) a_r = ω²r = (10500rad/s)² * 0.095m = 1.04e7 m/s²
which is 1.04e7 / 9.8 = 1.06e6 "g"s
(a little over 1 million "g"s)
31
Explanation: