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Ivenika [448]
3 years ago
10

What is the kinetic energy of a 3.8kg ball that is rolling at 2.2 m/s

Physics
1 answer:
labwork [276]3 years ago
3 0
Kinetic energy =  0.5 x m x v²
Kinetic energy = 0.5 x 3.8 x 2.2²
Kinetic energy = 9.196 J
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Explanation :

Formula used :

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Now put all the given values in the above formula, we get:

K.E=\frac{1}{2}mv^2

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6.8kg.m^2/s^2=\frac{1}{2}\times 0.046kg\times v^2

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