Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
A
Step-by-step explanation:
Answer:
h = A / ( 1/2 a - 1/2 b)
Step-by-step explanation:
A = ½ ah - ½ bh
Factor out an h
A = h( 1/2 a - 1/2 b)
Divide each side by ( 1/2 a - 1/2 b)
A / ( 1/2 a - 1/2 b) = h ( 1/2 a - 1/2 b)/ ( 1/2 a - 1/2 b)
A / ( 1/2 a - 1/2 b) = h
h = A / ( 1/2 a - 1/2 b)
Answer: 33 days.
Step-by-step explanation:
Given :- Camryn practices the trumpet every 11th day and the flute every 3rd day.
Camryn practiced both the trumpet and the flute today.
To find the number of days until Camryn practices the trumpet and flute again in the same day, we need to find the least common multiple (L.C.M.) of 11 and 3.
As they both are co-prime numbers thus its L.C.M.= 11×3=33
Therefore, Camryn practices the trumpet and flute again in the same day after 33 days.
Since the given figure is a trapezoid, here is how we are going to find for the value of x. Firstly, the sum of the bases of the trapezoid is always equal to twice of the median. So it would look like this. 2M = A + B.
Plug in the given values above.
2M = (<span>3x+1) + (7x+1)
2(10) = 10x + 2
20 = 10x + 2
20 - 2 = 10x
18 = 10x < divide both sides by 10 and we get,
1.8 = x
Therefore, the value of x in the given trapezoid is 1.8. Hope this is the answer that you are looking for.
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