Answer:
25%
Step-by-step explanation:
Great question, since a regular coin has two sides one heads and one tails. That gives us a 50% probability of it landing on either side of the coin. Since we would like to know the probability of getting 2 heads in a row, we would need to multiply the probability of the first toss landing on heads with the second toss landing on heads, like so...

So we can see that the probability of us getting two heads in a row is that of \frac{1}{4}[/tex] or 25%.
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72*12 = 2*2*2*2*2*3*3*3 = 2^5*3^3
Answer:
17.5 %
Step-by-step explanation:
5.6 is 17.5 percent of 32
Answer:
The answer to the problem is 3 1/2
Answer:
1/2 or 50% probability
Step-by-step explanation:
There are just two players, player A and player B. Since it is between this two players, for player A to score first we would have:
AB where player A is the first player to score, we wouldn't have BA since player would not be the first here
Probability = number of favorable outcomes/total number of outcomes
Therefore probability of A being the first player = number of A/total number of players
=1/2 = 0.50
There is therefore a 50% chance of A being the first player