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Phosphoric acid has 3 pKa values (pKa1=2.1, pKa2=6.9, pKa3= 12.4) and after 3 ionization it gives 3 types of ions at different pKa values:
H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq) pKₐ₁
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</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq) pKₐ₂
HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq) pKₐ₃
The last equilibrium is associated with the highest pKa value (12.4) of phosphoric acid. There the last OH group will lose its hydrogen and hydrogen phosphate ion (HPO₄²⁻) turns into phosphate ion (PO₄³⁻).
Answer:
Co
H20 somewhat ionic as well as covalent
SO2 is covalent
K2O is ionic
O2 ionic with somewhat covalent bonds
The solute is the part of the solution that dissolves in the second component (usually a fluid). Therefore, for the mentioned solution, the solute is ehyl alcohol since it is the one dissolving in water.
As for the solvent, it is the component in which the solute dissolves. In this case, it is water.
The serving of peanut butter contains 117kcal
<h3>Calculation of calories of food Nutrients</h3>
1 gram of both carbohydrate and protein contains 4 (kcal)
1 gram of fat contains 9 (kcal)
But peanut butter contains 5g of fat. The kilocalories of fat present is;
1 g = 9 kcal
5g = F
F = 5×9
F = 45 kcal
The kilocalories of carbohydrates present is;
1g = 4kcal
12g = C
C= 12×4
C = 48kcal
The kilocalories of proteins present is;
1g = 4kcal
6 g = P
P = 4× 6
P = 24 kcal
Therefore, the total kilocalories of the peanut = 45 + 48 + 24 = 117kcal
Learn more about kilocalories here:
brainly.com/question/6423812