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Olenka [21]
3 years ago
13

3. Write DISSOCIATION or IONIZATION equations for the following chemicals:

Chemistry
1 answer:
Romashka [77]3 years ago
8 0

Answer:

a) HNO3 -> H+ + NO3- disassociation of Nitric Acid; to yield a Nitrate ion and a Proton, H+, or as a Hydronium ion H3O+

b) H2S04 -> Disassociation of Sulfuric Acid; simple way- 2H+ + SO4- -

c) H2S hydrogen sulphide in water is an acid; thus H+ HS- disassociation.

d) NaOH -> dissociation of Na+ + OH-; this is complete; sodium hydroxide is deliquescent, meaning it will draw water - EVEN from the air! Strong Base

e) Na2CO3 -> 2Na+ CO3- - Ionization of sodium carbonate - a salt

f) Na2S04 -> 2Na+ + SO4 - - ionization of sodium sulphate - a salt

g) NaCl​ -> Na+ + Cl- ionization of the salt, Sodium Chloride

Explanation:

Salts ionize at different rates; acids or bases dissociate; these are mostly strong acids and NaOH, a strong base.

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Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

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d is distance between slits

\theta is the angle between the path and the line from screen to the slits.

We also know that, c=\nu \lambda

or

\lambda=\dfrac{c}{\nu}

where,

c is the speed of light

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So, equation (1) turns into

dsin\theta=n\dfrac{c}{\nu}

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So, correct option is (C).

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