Answer:
A. a system that can be affected by the outside environment, by an exchange of matter or energy
1 mol ---- 40g
X --------- 15g
X = 15/40 = 0,375 moles
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MThe heat energy required to raise the temperature of 0.36Kg of copper from 22 c to 60 c is calculate using the following formula
MC delta T
m(mass)= 0.360kg in grams = 0.360 x1000 = 360 g
c(specific heat energy) = 0.0920 cal/g.c
delta T = 60- 23 = 37 c
heat energy is therefore= 360g x0.0920 cal/g.c x 37 c= 1225.44 cal
Answer:
C. product costs and expensed when the goods are sold
Explanation:
