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3 years ago

Please I need help quickly Approximate the mean of the frequency distribution for the ages of the residents of a town.

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

5 0

Answer:

The mean age of the frequency distribution for the ages of the residents of a town is 43 years.

Step-by-step explanation:

We are given with the following frequency distribution below;

Age Frequency (f) X $X \times f$

0 - 9 30 4.5 135

10 - 19 32 14.5 464

20 - 29 12 24.5 294

30 - 39 20 34.5 690

40 - 49 25 44.5 1112.5

50 - 59 53 54.5 2888.5

60 - 69 49 64.5 3160.5

70 - 79 13 74.5 968.5

80 - 89 8 84.5 676

Total 242 10389

Now, the mean of the frequency distribution is given by the following formula;

Mean = $\frac{\sum X \times f}{\sum f}$

= $\frac{10389}{242}$ = 42.9 ≈ 43 approx.

Hence, the mean age of the frequency distribution for the ages of the residents of a town is 43 years.

Akimi4 [234]3 years ago

5 0

Answer:

The mean age of the frequency distribution for the ages of the residents of a town is 43 years.

Step-by-step explanation:

We are given with the following frequency distribution below;

Age Frequency (f) X

0 - 9 30 4.5 135

10 - 19 32 14.5 464

20 - 29 12 24.5 294

30 - 39 20 34.5 690

40 - 49 25 44.5 1112.5

50 - 59 53 54.5 2888.5

60 - 69 49 64.5 3160.5

70 - 79 13 74.5 968.5

80 - 89 8 84.5 676

Total 242 10389

Now, the mean of the frequency distribution is given by the following formula;

Mean =

= = 42.9 ≈ 43 approx.

Hence, the mean age of the frequency distribution for the ages of the residents of a town is 43 years

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Hi please help i’ll give brainliest please

tatiyna

Answer:

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3 years ago

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musickatia [10]

Answer:

Step-by-step explanation:

plug 3 into m and plug 1 into n
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3 years ago

Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio

s344n2d4d5 [400]

Answer:

A) $\frac{1}{1024},\frac{1}{4096}$

B) $\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

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Step-by-step explanation:

1) Incomplete question. So completing the several terms: $\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}$

We can realize this a Geometric sequence, with the ratio equal to:

$q=\frac{1}{4}$

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

$\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}$

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

$\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

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$\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

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3 years ago

Pls answer the question attached

barxatty [35]

$\huge\mathfrak{\underline{answer:}}$

$\large\bf{\angle ACD = 105°}$

__________________________________________

$\large\bf{\underline{Here:}}$

BCD is an isosceles right triangle , right angled at D
ABC is an equilateral triangle

$\large\bf{\underline{To\:find:}}$

∠ ACD

$\large\bf{In\: triangle\:ABC:}$

❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same

$\large\bf{\underline{So}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = \frac{180}{3}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = 60°}$

$\large\bf{In\: triangle\:BDC}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle D = 90°}$

$\bf{⟼\angle DBC =\angle DCB }$ (Isosceles triangle)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DBC + \angle BDC + \angle DCB = 180° }$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB + 90° = 180°}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB = 180 -90}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = \frac{90}{2}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = 45°}$

$\large\bf{\underline{Therefore,}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = \angle ACB + \angle DCB}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = 60+45}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹\angle ACD = 105°}$

6 0

3 years ago

Given the function f(x) = 2x-5 and g(x), which function has a greater slope?

adell [148]

Answer:

g(x) has a greater slope

Step-by-step explanation:

step 1

Find the slope of f(x)

we have

$f(x)=2x-5$

This is a linear function in slope intercept form

$f(x)=mx+b$

where

m is the slope

b is the y-intercept

$m=2$

step 2

Find the slope of g(x)

take two points from the table

(2,0) and (4,5)

$m=(5-0)/(4-2)\\m=5/2=2.5$

step 3

Compare the slopes

$2.5 > 2$

The slope of g(x) is greater than the slope of f(x)

3 0

4 years ago

*Please I need help quickly* Approximate the mean of the frequency distribution for the ages of the residents of a town.

Please I need help quickly Approximate the mean of the frequency distribution for the ages of the residents of a town.