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Jobisdone [24]
3 years ago
9

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x2 + 5x

= 300. What are the measures of the width and the length?
Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

  width: 15 inches; length: 20 inches

Step-by-step explanation:

The equation tells you the product of width (x) and length (x+5) is 300, so you're looking for factors of 300 that differ by 5.

  300 = 1·300 = 2·150 = 3·100 = 4·75 = 5·60 = 6·50 = 10·30 = 12·25 = 15·20

The factors in the last pair on this list differ by 5, so we have ...

  • width = 15 inches
  • length = 20 inches
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Eliminate the parameter and obtain the standard form of the rectangular equation. line through (x1, y1) and (x2, y2): x = x1 + t
Helen [10]

The parametric equations for the line passes through the points (X₁ , Y₁) and (X₂ , Y₂) are :

X = X₁ + t (X₂ - X₁) ......................... (1)

Y = Y₁ + t (Y₂ - Y₁) .......................... (2)

For eliminating the parameter (t) , first we will solve any one equation for 't' and then substitute that into another equation.

From the equation (1),

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Substituting this t = \frac{X- X1}{(X2 - X1)} into the equation (2), we will get :

Y = Y₁ + \frac{(X- X1)}{(X2 - X1)} (Y₂ - Y₁)

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So, this is the standard form of rectangular equation.

For two given points (0, 0) and (4, -4)

X₁ = 0 , Y₁ = 0, X₂ = 4 and Y₂ = -4

For finding the parametric equations, we will plug these values into the given parametric equations.

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So, the parametric equations for the line passing through (0,0) and (4, -4) are: X = 4t and Y = -4t

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3 years ago
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