Step-by-step explanation:
whenever a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial. as an example, we'll find the roots of the polynomial..
x^5 - x^4 + x^3 - x^2 - 12x + 12.
the fifth-degree polynomial does indeed have five roots; three real, and two complex.
Subtract 153-63=90 and I am pretty sure that's what you have to do
1s -0
5s- 1
25s- 0
125s- 0
625s- 2
3125s- 0
15625s- 2
2020010. I think this is right but would like so confirmation, just taught myself this!
Answer:
c
Step-by-step explanation:
Applying log rules leaves us with the following equation:
x^2 + 8 = 6x
Change to standard form and solve using factoring.
x^2 - 6x + 8 = 0
(x - 4)(x - 2) = 0
x = 4
x = 2
Hope this helps!
