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3 years ago

The scale in the drawing is 2in:4ft. What are the length and width of the actual room find the area of the actual room

Mathematics

2 answers:

Marizza181 [45]3 years ago

6 0

1:24 get them each doqwn 1 inch 24 inche = 2 feet

steposvetlana [31]3 years ago

4 0

2 in = 4 ft. then

14 in = 28 ft. ( 14/2=7 7x4=28)
7in = 14 ft. (7/2 = 3.5 x 4= 14)
then

area = l x w
28 x 14 =
392 ft

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3 years ago

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34kurt

Answer:

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Step-by-step explanation:

Since we know -7x=y we use the substitution method and plug it in the top equation.

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3 years ago

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3 years ago

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brainly.com/question/4397823

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2 years ago

Find the area of a regular octagon with a perimeter of 80 ft and an apothem of 12.07 feet

Finger [1]

Answer:

The area of a regular octagon with a perimeter of 80 ft and an apothem of 12.07 feet is 482.8 ft².

Step-by-step explanation:

An octagon is a polygon with eight sides. An octagon is regular (also called a regular octagon) is a polygon with all eight sides equal.

The apothem of a regular octagon is the shortest distance between the center and any of its sides, in other words, it is the distance that separates the center of the polygon from the central point of each side of the octagon.

The area is calculated using the following formula:

$Area=\frac{n*L*Ap}{2}$

Where:

n is the number of sides.
L is the length of one of the sides.
Ap is the value of the apothem.

Being n = 8 being an octagon and the perimeter P the sum of the sides of the octagon (P = 8 * L), the area of the regular octagon can be calculated by:

$Area=\frac{P*Ap}{2}$

In this case:

P=80 ft
Ap=12.07 ft

Replacing:

$Area=\frac{80ft*12.07ft}{2}$

Solving:

Area=482.8 ft²

<u><em>The area of a regular octagon with a perimeter of 80 ft and an apothem of 12.07 feet is 482.8 ft².</em></u>

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3 years ago