Let x be the distance (in feet) along the road that the car has traveled and h be the distance (in feet) between the car
and the observer.
(a) Before the car passes the observer, we have dh/dt < 0; after it passes, we have dh/dt > 0. So at the instant it passes the observer we have
dh/dt = 0, given that dh/dt varies continuously since the car travels at a constant velocity.
X=3
X/-3 = -1 ,Leave X by itself so multiply by -3 on both sides.
X = -1*-3
X = 3, negative times negative equals positive.
5:8
is the ratio .he she and shd
Start with
Separate the variables:
Integrate both parts:
Which implies
Solving for y:
Since 
is itself a constant, let's rename it 
.
Fix the additive constant imposing the condition:
So, the solution is
The exponential formula for this situtation will be given by:
f(x)=ae^(-bx)
where:
a=initial price
b=rate
x=time in years
hence the formula will be:
f(x)=28750e^(-0.12x)
thus the value of the car in 2018 will be:
x=2018-2012=6 years
thus
f(6)=28750e^(-0.12*6)
f(6)=$13,994.13
