The only expressions that are correctly factored are;
A) 16a⁵ - 20a³ = 4a³(4a² - 5)
B) 24a⁴ + 18 = 6(4a⁴ + 3)
C) 12a³ + 8a = 4a(3a² + 2)
D) 30a⁶ - 24a² = 3a²(10a⁴ - 8)
<h3>How to factorize equations?</h3>
1) 16a⁵ - 20a³
To factorize this, we will have to get out the common factor first. The common factor is 4a³. Thus, we now have;
4a³(4a² - 5)
2) 24a⁴ + 18
To factorize this, we will have to get out the common factor first. The common factor is 6. Thus, we now have;
6(4a⁴ + 3)
3) 12a³ + 8a
To factorize this, we will have to get out the common factor first. The common factor is 4a. Thus, we now have;
4a(3a² + 2)
4) 30a⁶ - 24a²
To factorize this, we will have to get out the common factor first. The common factor is 3a². Thus, we now have;
3a²(10a⁴ - 8)
Read more about factorization of equations at; brainly.com/question/723406
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Answer:
c = 2 *pie* r
Step-by-step explanation:
Answer:
On a standard running 400-meter track a mile is 4 laps… plus 9 more meters if you want to get all technical about it. A mile is specifically 1,609.3 meters.
Step-by-step explanation:
Answer: 20+35=55+20=75
Step-by-step explanation:
Answer:
x = 5 and x = -19
Step-by-step explanation:
You're on the right track. It's the "discriminant" that tells you what you want to know here. Before starting, arrange the terms of your quadratic in descending orders of x: 5x^2 + 14x - 19 = 0 (Note that I assumed you meant 14x instead of just 14).
Then the coefficients of this quadratic are a = 5, b = 14 and c = -19.
You are referring to the "quadratic formula." It states this:
-b ± √(b²-4ac)
x = -----------------------
2a
So, we insert the a, b and c values as indicated above:
-14 ± √( 14² - 4[5][-19] ) -14 ± √(196 - 4[5][-19] ) -14 ± √576
x = ----------------------------------- = ---------------------------------- = ----------------------
2(10) 20 20
This comes out to:
x = (-14 + 24) / 2 and x = (-14 - 24) / 2
or:
x = 5 and x = -19
