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horsena [70]
3 years ago
14

PLEASE HELP ME

Mathematics
2 answers:
lyudmila [28]3 years ago
6 0
As seen, the graph is pointing/increasing upwards. This means that the graph is exponentially increasing. 

You notice there are significantly more spores at 4th hour than the first, therefore, this is an increasing trend. 

Hope I helped :) 
NemiM [27]3 years ago
6 0

Answer: growth, and increases

Step-by-step explanation:

You might be interested in
Camryn enlarged the size of a photo to a height of 18 inches, what is the
patriot [66]

Answer:

I'm think is 17

Step-by-step explanation:the Height of it was 18 and the original height was 2 so subtract 2 from 18 you get 16.So thy are adding 16.So 16+1=17.

4 0
2 years ago
1. Thom has a scale model of his car. The
MariettaO [177]

x =\frac{4}{3}inch is the size in wheels on the scale model .

<u>Step-by-step explanation:</u>

Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?

We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:

Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,

⇒ \frac{1}{12}  = \frac{x}{16}                 { x is size of wheel in scale model }

⇒ \frac{1(16)}{12}  = \frac{x}{16}(16)

⇒ x =\frac{16}{12}

⇒ x =\frac{4}{3}inch

Therefore , x =\frac{4}{3}inch is the size in wheels on the scale model .

5 0
3 years ago
I need help please
nlexa [21]

Answer:

49

Step-by-step explanation:

No she is not correct because we dont have only one angle angle G is 90.

So we can easily find the angle D

180-(90+41) =49

7 0
2 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
3 years ago
Please anyone help me with this?!​
andriy [413]

Answer:

It would be 55.88 but if you round it it would be 55.9 then round it again it would be 56%.

7 0
3 years ago
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