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Novosadov [1.4K]
4 years ago
9

In Young’s double-slit experiment using monochromatic light, the interference pattern consists of a central _____.

Physics
1 answer:
NNADVOKAT [17]4 years ago
4 0

Answer:

In Young’s double-slit experiment using monochromatic light, the interference pattern consists of a central <u>MAXIMUM</u>.

Explanation:

In Young's double slit method of experiment we know that on the screen we have light of monochromatic source.

Due to this double slit system when light reaches to the screen there exist a finite path difference on the screen and which will create phase difference between two light reaches on the screen

It is given as

\Delta \phi = \frac{2\pi}{\lambda}(Path difference)

so here if path difference is zero due to two slits at the center of the screen

Then in that case

\Delta \phi = \frac{2\pi}{\lambda}(0) = 0

so we will have maximum intensity at the center of the screen when light will reach at the center of the screen.

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Answer:

Please see below as the answer is self-explanatory.

Explanation:

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Answer:

Option C.

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Explanation:

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Momentum = mv

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Change in momentum = mΔv

Thus,

Impulse = change in momentum

Impulse = mass × change in velocity

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