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3 years ago

10

What is impossible for a machine to do

2 answers:

oee [108]3 years ago

4 0

Answer:

Create a living person.

Explanation:

Annette [7]3 years ago

4 0

Answer: It is impossible for a machine to do a lot of things, like talk like humans, walk, or even speak. A machine is used for making humans lives easier such as a vending machine or a coin machine.

Explanation:

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When the mass of an object decreases, the force of gravity

Viktor [21]

Hello There!

From what i know, gravitational force increases if the mass is increased.
If the mass is being decreased, then i assume it will be B. Decreases.

Hope This Helps You!
Good Luck :)

- Hannah ❤

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3 years ago

Problem set 3 » (8) river swimming a swimmer heads directly across a river, swimming at her maximum speed of 1.30 m/s relative t

jasenka [17]

Velocity of swimmer across river = 1.30 m/s

Distance arrived downstream = 48 m

Width of river = 64 m

Time taken to cross river = $\frac{Width of river}{Velocity across river}$

= $\frac{64}{1.30} =49.23 s$

Speed of river current = $\frac{Distance arrived downstream}{Time taken to cross river}$

= $\frac{48}{49.23} = 0.975 m/s$

So, the river is flowing at a speed 0.975 m/s.

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3 years ago

A scientist proposed a hypothesis that burning coal at higher altitudes would release less pollution. The data the scientist col

Nadusha1986 [10]

Answer: i really don't know bu i recomened you watch josie b asmr she is the best

Explanation:

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3 years ago

Someone please help me!

beks73 [17]

Answer:

current = 8,750

Explanation:

you will need to use the formula i = v/r to get this answer

3 0

3 years ago

hat are the wavelengths of peak intensity and the corresponding spectral regions for radiating objects at (a) normal human body

bagirrra123 [75]

Answer:

(a)

$\lambda _{m}=9.332 \times 10^{-6}m$

(b)

$\lambda _{m}=1.632 \times 10^{-6}m$

(c) $\lambda _{m}=4.988 \times 10^{-7}m$

Explanation:

According to the Wein's displacement law

$\lambda _{m}\times T = b$

Where, T be the absolute temperature and b is the Wein's displacement constant.

b = 2.898 x 10^-3 m-K

(a) T = 37°C = 37 + 273 = 310 K

$\lambda _{m}=\frac{b}{T}$

$\lambda _{m}=\frac{2.893\times 10^{-3}}{310}$

$\lambda _{m}=9.332 \times 10^{-6}m$

(b) T = 1500°C = 1500 + 273 = 1773 K

$\lambda _{m}=\frac{b}{T}$

$\lambda _{m}=\frac{2.893\times 10^{-3}}{1773}$

$\lambda _{m}=1.632 \times 10^{-6}m$

(c) T = 5800 K

$\lambda _{m}=\frac{b}{T}$

$\lambda _{m}=\frac{2.893\times 10^{-3}}{5800}$

$\lambda _{m}=4.988 \times 10^{-7}m$

5 0

3 years ago