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N76 [4]
3 years ago
6

Sabendo que senx=3/5 e que X € 1°quadrante, calcule tgx

Mathematics
1 answer:
guapka [62]3 years ago
4 0
<span>se 
sen x = 3/5 eleva ao quadrado ambos os lados 
sen² x = (3/5)² 

Tem que partir da relação fundamental 

sen²x + cos²x = 1 
(3/5)² + cos² x = 1 

cos² x = 1 - (3/5)² = 16/25 

cos x = V(16/25 = 4/5 

b ) tg x = sen x / cos x = 3/5 / 4/5 = 3/5 * 5/4 = 3/4 

c) cotg x = cosx / sen x = 1 / tgx = 1/ (3/4 = 4/3 

d) sec x = 1/ cos x = 1 / 4/5 = 5/4 

e) cossec x = 1 / sen x = 1/ 3/5 = 5/3 

se gostou , avalie 
edson</span>edson <span>· 9 anos atrás</span>
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