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Bumek [7]
2 years ago
15

For the equation y - 3 = -2(x + 1) the line has a slope of -2 and contains what point

Mathematics
2 answers:
Westkost [7]2 years ago
6 0
It contains multiple points. If you’re looking specifically for a point plug the number that is on the x axis into the equation then solve for y.

yarga [219]2 years ago
6 0

Answer:

(0, -2) --> Y-Intercept

Step-by-step explanation:

y - 3 = -2( x + 1 )

y - 3 = -2x - 2

y= -2x -2

Y-Intercept = (0,y)

= (0, -2)

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What are the potential solutions to the equation 2ln(x+3)=0
skad [1K]
2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1

Expanding the left side gives

x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0

which gives two solutions, x=-4 and x=-2. But if x=-4, then \ln(x+3)=\ln(-1), but this number isn't real, so x=-4 is an extraneous solution. Meanwhile if x=-2, you get \ln(-2+3)=\ln1=0, so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
4 0
3 years ago
Read 2 more answers
Working alone, it would take Shandra 40 minutes to sand a table. To sand the same table, also working alone, it would take
egoroff_w [7]

Answer:  it will take them about 24 minutes working together

Step-by-step explanation:

1/40    +   1/60 =

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Cross multiplication:

1*t = 1*24  

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3 0
2 years ago
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Solve for e.<br><br> 4/3=-6e-5/3
cricket20 [7]

Answer:

e = 1/2

Step-by-step explanation:

to solve foe e in  this 4/3=-6e-5/3

solution

4/3=-6e-5/3

4/3 + 5/3 = 6e

find the lcm of the left hand side

4 + 5/3 = 6e

9/3 = 6e

cross multiply

3 x 6e = 9 x 1

18e = 9

divide both sides by the coefficient of e which is 18

18e /18 = 9/18

e = 1/2

therefore the value of e in the expression above is evaluated to be equals to 1/2

5 0
3 years ago
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Shtirlitz [24]
Yes because you only need a 90 degree to become a right
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3 years ago
Are the two expressions equivalent 5(3x+8) 8x+8 when x=10
Brums [2.3K]

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5(3(10)+8)

5(30+8)

5(38)=190

8(10)+8

80+8

88

88≠190 so no

7 0
3 years ago
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