D) EFGH moved onto E'F'G'H after rotating 180 counterclockwise around the origin and the reflecting across the y-axis.
<h3>How to carry out transformations?</h3>
From online resources gotten about this question, for quadrilateral EFGH and quadrilateral E'F'G'H to be congruent, what we must do first is to rotate 180° counterclockwise around the origin and then move EFGH onto E'F'G'H'.
The last step to get this proof of congruency is to reflect across the y-axis.
Read more about transformations at; brainly.com/question/4289712
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22-2=m-7.
first you subtract 22-2 thats 20.
then youtake 20 and subtract it by 7 but in order to do that you have to make 20 negative.
m-7
- 20
this equals m-20
6w-y=2z
6w=2z+y
w=(2z+y):6
w=(z:3)+(y:6)
Answer:
-23
Step-by-step explanation:
Let first negative integer = x
The second = x +5
Their product = 126, hence,
x * (x +5) = 126
x^2 + 5x = 126
x^2 + 5x - 126 = 0
Two numbers whose product gives - 126 and sun gives 5
x(x + 14) - 9(x+14) =0
(x - 9) = 0 or (x + 14) = 0
x = 9 or x = - 14
Since x is said to be a negative integer,, the our x = - 14
First integer = - 14
Second integer = (x + 5) = (-14 + 5) = - 9
Sum of both integers :
-14 + - 9 = - 23