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IgorC [24]
3 years ago
14

Can someone help me

Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

w = 10 cm

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = \frac{1}{2} base × height

here base = 6 and height = 8, thus

A = 0.5 × 6 × 8 = 3 × 8 = 24 cm²

The area of the rectangle = 5 × 24 = 120 cm²

area of rectangle = lw ( l is length, w is width )

Here l = 12, thus

120 = 12w ( divide both sides by 12 )

w = 10 cm

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3 years ago
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Inessa05 [86]

Answer:

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3. d=3.16

4. v=1.4

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Step-by-step explanation:

3 0
2 years ago
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Find the product. Write your answer in<br> exponential form.<br> 6^-4•6^-9
Karolina [17]

Answer:

6^-13

Step-by-step explanation:

The rule for multiplying numbers with the same base but different exponents is a^b*a^c=a^(b+c), so in this case we have 6^(-4+(-9)) which is 6^-13

Hope this helped!

6 0
3 years ago
John took all his money from his savings account. He spent $88 on a radio and 1/4 of what was left on presents for his friends.
gayaneshka [121]

Answer:

$968

Step-by-step explanation:

x= the money John originally had in his savings account

The statement says that John spent $88 on a radio and 1/4 of what was left on presents for his friends. This means that the remaining money is 3/4 of the total amount minus the money spent on the radio:

3/4(x-88)

Then, it says that of the money remaining, John put 4/11 into a checking account and the last remaining $420 was left to charity. Since, he spent 4/11 of the remining 3/4(x-88), the remaining is 7/11 of that and that remaining is equal to $420 that was the money left at the end:

7/11(3/4(x-88))= 420

21/44(x-88)=420

21/44x-42=420

21/44x=462

x=968

According to this, the money that John originally had in his savings account was $968.

He spent $88 on a radio: 968-88= 880

1/4 of what was left on presents for his friends: 880/4= 220

880-220=660

Of the money remaining, John put 4/11 into a checking account: 660*(4/11)=240

the last remaining $420 was left to charity: 660-240= 420

6 0
3 years ago
In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
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