Let's plug the values and see which couple satisfy the equation: since $y = 2\cdot 3^x$ , if we plug the values from the first option $(x,y)=(1,6)$ we have

$6 = 2\cdot 3^1 = 2\cdot 3$

which is correct.

If we plug the values from the second option $(x,y)=(1,9)$ we have

$9 = 2\cdot 3^1 = 2\cdot 3$

which is not correct

If we plug the values from the third option $(x,y)=(2,9)$ we have

$9 = 2\cdot 3^2= 2\cdot 9$

which is not correct

If we plug the values from the fourth option $(x,y)=(2,12)$ we have

$12 = 2\cdot 3^2= 2\cdot 9$

which is not correct

So, the answer is the first one.

3 0

3 years ago

Help me answer this question people will give brainliest

lana66690 [7]

Answer:It'll be part B

Step-by-step explanation:

5 0

3 years ago

How do we solve an equation with variables on both sides

HACTEHA [7]

You combine those variables, then solve.

hope that helps :) ✨

4 0

4 years ago

Jaizelyn is sewing pillow and quilt sets for a customer. Each set has 2 pillows and 1 quilt. She uses 0.75 yards of material for

Ray Of Light [21]

Set= 2 pillows + quilt
Set= (2×0.75)+12
Set= 13.5
3 sets= 3×13.5
3 sets=40. 5

3 0

3 years ago