DO ANYONE KNOW HOW TI FIND THE AREA OF A REGULAR POLYGON?? ill give brainlest and points

Mathematics

2 answers:

zloy xaker [14]4 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

The area (A) of a regular decagon ( 10 sided ) is calculated as

A = 0.5 × perimeter × apothem

Here side length = 3.25, hence perimeter = 10 × 3.25 = 32.5 m, thus

A = 0.5 × 32.5 × 5 = 81.25 m²

leva [86]4 years ago

4 0

Answer:

Regular decagon

Solve for areap

A=5/2a²√5+2√5

Step-by-step explanation:

apothem

No.of Sides of Polygon

Length of each side

3.25

Unit : in

Area of Polygon = 40.625in2

Formula

The following mathematical formula is used in this regular plygon area calculator to find the area from the given input value of apothem, number of sides & length of side.

Rectangle Polygon Area A = (1/2) Apothem x No. of Sides x Length of side

plz Mark me brainliest answer

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AP Calculus redo! I know the answer but can't figure out exactly how to get there. Thank you! I want to work through the steps.

Monica [59]

You're approximating

$\displaystyle\int_1^5 x^2\,\mathrm dx$

with a Riemann sum, which comes in the form

$\displaystyle\int_a^b f(x)\,\mathrm dx=\lim_{n\to\infty}\sum_{i=1}^nf(x_i)\Delta x_i$

where $x_i$ are sample points chosen according to some decided-upon rule, and $\Delta x_i$ is the distance between adjacent sample points in the interval.

The simplest way of approximating the definite integral is by partitioning the interval into equally-spaced subintervals, in which case $\Delta x=\dfrac{b-a}n$ , and since $[a,b]=[1,5]$ , we have

$\Delta x=\dfrac{5-1}n=\dfrac4n$

Using the right-endpoint method, we approximate the area under $f(x)$ with rectangles whose heights are determined by their right endpoints. These endpoints are chosen by successively adding the subinterval length to the starting point of the interval of integration.

So if we had $n=4$ subintervals, we'd split up the interval of integration as

$[1,5]=[1,2]\cup[2,3]\cup[3,4]\cup[4,5]$

Note that the right endpoints follow a precise pattern of

$2=1+\dfrac44$
$3=1+\dfrac84$
$4=1+\dfrac{12}4$
$5=1+\dfrac{16}4$

The height of each rectangle is then given by the values above getting squared (since $f(x)=x^2$ ). So continuing with the example of $n=4$ , the Riemann sum would be

$\displaystyle\sum_{i=1}^4\left(1+\dfrac{4i}4\right)^2\dfrac44$

For $n=5$ ,

$\displaystyle\sum_{i=1}^5\left(1+\dfrac{4i}5\right)^2\dfrac45$

and so on, so that the definite integral is given exactly by the infinite sum

$\displaystyle\lim_{n\to\infty}\sum_{i=1}^n\left(1+\dfrac{4i}n\right)^2\dfrac4n$