Answer: 4
There are three different ways to find the remainder. Since I don't know which lesson you are working on, I will show you all three methods.
<u>Long Division:</u>
<u>3x + 7 </u>
2x - 1 ) 6x² + 11x - 3
- <u>(6x² - 3x)</u> ↓
14x - 3
- (<u>14x - 7)</u>
4
<u>Synthetic Division:</u>
2x - 1 = 0 ⇒ x = 
| 6 11 -3
<u>| ↓ 3 7</u>
6 14 4
<u>Remainder Theorem:</u>
2x - 1 = 0 ⇒ x = 
f(x) = 6x² + 11x - 3
f(
) = 6(
)² + 11(
) - 3
= 6(
) +
- 3
=
+
- 
= 
= 4
Subtract 3x from both sides:
-6y = -3x + 6
divide both sides by -6 to get y by itself:
y = 1/2x - 1
function notation is rewriting y as a function:
f(x) = 1/2x -1
If I’m doing it correctly it’s 2/3 but I haven’t done it in a while