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3 years ago

How many solutions does the system of equations below have?

Mathematics

2 answers:

BaLLatris [955]3 years ago

6 0

Answer:

C: none

Step-by-step explanation:

Here we have two separate functions named 'y.' Eliminate 'y' temporarily by equating these functions together:

x + 2 = y = x - 1

Subtracting x from both sides, we get:

0 + 2 = y = 0 - 1, or

2 = -1

This is never true, so C is the correct answer: NO solutions.

An easier way in which to do this problem is to visualize the graphs of

y = x + 2 and y = x - 1. The graphs are parallel straight lines; they never intersect, and therefore we can conclude "no solution."

galben [10]3 years ago

4 0

Answer:

Step-by-step explanation:

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Solve using linear combination. 8x+14y=4 -6x-7y+-10

emmasim [6.3K]

It's best to write the two equations as a vertical column:

8x+14y=4

-6x-7y = -10

Note that if we multiply the 2nd equation by 2, we get -12x - 14y = -20. The reason for wanting this version of the 2nd equation is that its -14y cancels the +14y in the first equation:

-12x - 14y = -20

8x+14y=4

Combine these equations, column by column. We get -4x = -16, which results in x = 4. Now find y by subbing 4 for x in either given equation. If we use the first equation, we get 8(4) + 14y = 4, or 32 + 14y = 4, or 14y = -28. Then y = -2.

The solution to this system of linear equations is thus (4,-2).

Check this result by substitution of these coordinates into -6(4) - 7y = -20:

-24 - 7(-2) = -10. Is this true or not?

-24 + 14 = -10 is true. Thus, (4,-2) is the desired solution.

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2 years ago

Solve each question mentally <br> -3x = 21

Snowcat [4.5K]

X = -7

3 • 7 = 21

-3 • (-7) = 21

If you multiply two negative numbers you’ll end up with a positive. Thus, - 3 (-7) = 21.

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2 years ago

You deposit $100 in a savings account. The account earns 11% simple interest per year.

qaws [65]

Answer:

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3 years ago

Need help ASAP

joja [24]

Part (1) : The solution is $729$

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

Explanation:

Part (1): The expression is $3^{2} \cdot3^{4}$

Applying the exponent rule, $a^{b} \cdot a^{c}=a^{b+c}$ , we get,

$3^{2} \cdot 3^{4}=3^{2+4}$

Adding the exponent, we get,

$3^{2} \cdot3^{4}=3^6=729$

Thus, the simplified value of the expression is $729$

Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\left(2 x^{2}\right)^{-4}=\frac{1}{\left(2 x^{2}\right)^{4}}$

Simplifying the expression, we have,

$\frac{1}{2^4x^8}$

Thus, we have,

$\frac{1}{16 x^{8}}$

Thus, the value of the expression is $\frac{1}{16 x^{8}}$

Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

Applying the exponent rule, $\frac{x^{a}}{x^{b}}=x^{a-b}$ , we have,

$\frac{2x^{4-2}y^{-4+3}z^{-3-4}}{3}$

Adding the powers, we get,

$\frac{2x^{2}y^{-1}z^{-7}}{3}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

8 0

3 years ago

Why is 1 neither prime nor a composite number?

Nadya [2.5K]

Answer:

1 is neither prime nor a composite number because it only has 1 divisor, 1 and 1, and it doesn't have more than 2 integral divisors, like stated, it only has 1. So it falls in neither category.

7 0

2 years ago

Read 2 more answers