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kati45 [8]
3 years ago
12

How do Solve these equations

Mathematics
1 answer:
arsen [322]3 years ago
4 0

I can’t do these right off hand but look them up on google and google will tell you exactly how to do and if you type in the problem it will explain how to the the problem as well , I hope you understand and this helped you.

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Explain the difference between the translation of y=x² for the graphs of y=(x+3)² and y=x²+3.​
LUCKY_DIMON [66]

Answer:

y=(x+3)^2 has a vertex at (-3,0), while y=x^2 + 3 has a vertex at (0,3)

Mark me brainliest hope this helps

Step-by-step explanation:

3 0
2 years ago
First, break the irregular polygon into shapes whose (select)
Olegator [25]

The area of a shape is the amount of space it occupies

The complete statement is: First, break the irregular polygon into shapes whose area you can find using familiar formulas. The sum of these areas is the area of the polygon.

<h3>How to determine the area of an irregular polygon</h3>

An irregular polygon contains several familiar shapes.

So, the first thing to do is to break the polygon into smaller shapes

Then calculate the areas of these shapes

Lastly, add the areas of the shapes to get the area of the irregular polygon

Hence, the area of an irregular polygon is the sum of the areas of the shapes that make up the irregular polygon

Read more about areas at:

brainly.com/question/24487155

3 0
2 years ago
HELP PLEASE 50 points !!! Given a polynomial function describe the effects on the Y intercept, region where the graph is incre
Gwar [14]

Even function:

A function is said to be even if its graph is symmetric with respect to the , that is:

Odd function:

A function is said to be odd if its graph is symmetric with respect to the origin, that is:

So let's analyze each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When  becomes  

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

We know that the graph  intersects the y-axis when , therefore:

So:

So the y-intercept of  is one unit less than the y-intercept of

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function  increases and decreases in the same intervals of

1.3 The end behavior when the following changes are made.

The function is shifted one unit downward, so each point of  has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:

FOR ODD FUNCTIONS:

2. When  becomes  

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.

An example is shown in Figure 1. The graph in blue is the function:

and the function in red is:

So you can see that:

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of

In Figure 1 you can see that both functions increase at:

and decrease at:

2.3 The end behavior when the following changes are made.

It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When  becomes  

3.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

As we know, the graph  intersects the y-axis when , therefore:

And:

So the new y-intercept is the negative of the previous intercept shifted one unit upward.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

3.3 The end behavior when the following changes are made.

Each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:

FOR ODD FUNCTIONS:

4. When  becomes  

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward.

6 0
3 years ago
A chicken farmer also has cows for a total of 30 animals, and the animals have 66 legs in all. How many chickens does the farmer
hammer [34]

Answer:

27 chickens

Step-by-step explanation:

A chicken farmer also has cows for a total of 30 animals

Both animals have a total of 66 legs

Let a represent the number of chicken

Let b represent the number of cows

a + b= 30........equation 1

Since a chicken has only two legs and a cow has four leg then, the expression can be represented as

2a + 4b= 66........equation 2

From equation 1

a + b= 30

a = 30-b

Substitute 30-b for a in equation 2

2a + 4b= 66

2(30-b) + 4b= 66

60 - 2b + 4b= 66

60 + 2b= 66

2b= 66-60

2b= 6

b= 6/2

b= 3

Substitute 3 for b in equation 1

a + b = 30

a + 3=30

a= 30-3

a= 27

Hence the farmer has 27 chickens

5 0
3 years ago
Find the center of the circle that you can circumscribe about EFG, when E(2, 6), F(2, 2), and G(8, 2).
Vlad1618 [11]
After plotting all the points, the only one that makes sense is (4,3).

7 0
3 years ago
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