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2 years ago

How do Solve these equations

Mathematics

1 answer:

arsen [322]2 years ago

4 0

I can’t do these right off hand but look them up on google and google will tell you exactly how to do and if you type in the problem it will explain how to the the problem as well , I hope you understand and this helped you.

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X - - 3 = 10 <br><br> What is the value of x?

Pepsi [2]

Answer:

x = 7

Step-by-step explanation:

Rule: an even number of - signs written one after another produces a plus number.

So - - 3 = 3

The rule also lets you do something strange like

- - - - 4 = 4 but you hardly ever see this.

Rule: an odd number of minus signs produces a minus number.

x + 3 = 10 Subtract 3 from both sides.

x + 3 - 3 = 10 - 3

x = 7

4 0

2 years ago

Read 2 more answers

Solve for X (simplify your answer)

lora16 [44]

Answer:

x is given as -1.5. Substitute to confirm

7 0

2 years ago

A town's yearly snowfall in inches over a 10-year period is recorded in this table. What is the mean of the snowfall amounts?

lawyer [7]

So to find the mean you add them all together and divide by the number of numbers there is so 11+15+19+17+23+20+17+18+21=174 and there are 10 numbers so it would be 174/10 which is 17.4 so you answer is 17.4

4 0

2 years ago

A line that intersects two or more lines is called a parallel line true or false

Irina18 [472]

Answer:

False

Step-by-step explanation:

Parallel lines never touch

6 0

3 years ago

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago