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bixtya [17]
3 years ago
11

-4(4-4v)-v=-2(-5v-2) answer

Mathematics
2 answers:
erastova [34]3 years ago
7 0
-16 + 15v = 10v + 4

15v - 10v = 16 + 4

5v = 20

v =20/5

v =4
nalin [4]3 years ago
3 0

Answer:

Step-by-step explanation:

-16-16v - v = 10v + 4

Add 16 to both sides and combine like terms giving you

15v = 10v + 20

Subtract 10v from both sides

5v= 20

Divide by 5

V=4

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Find the difference (10m+3)-(4m-2)
pshichka [43]

Answer:

6m + 5

Step-by-step explanation:

3 0
3 years ago
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
3 years ago
14
uranmaximum [27]

Answer:

x = 2515

Step-by-step explanation:

5000 = 2x - 30

2800 = x

<h2>have a great day! I hope this helps! </h2>
4 0
2 years ago
Round 715 to the nearest the ten
Mariana [72]
Here's a good rhyming rule to keep in mind.

Zero to four, you get no more.

Five to nine, move up one time.

With this rule you can see that there is a 5 at the end, therefor you should round up. Your number is 720.
8 0
3 years ago
Read 2 more answers
How many simple interest accrues on a $5,000 loan at 8% for 18 months?
katen-ka-za [31]

Answer:

$600

Step-by-step explanation:

A = P(1 + rt)

P is the Principal amount of money to be invested at an Interest Rate R% per period for t Number of Time Periods.

A= 5,000(1+ 0.08x1.5) = $5600

5 0
3 years ago
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