This is a very confusing question since it sounds more like a statement. sorry really wish I could help :(
Answer:
I'm pretty sure the answer is C
Explanation:
Sorry if wrong.
Answer:
Im pretty sure its C. But correct me if im wrong
X: Gastropods
Y: Cephalopods
Z: Bivalves
Explanation:
Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
Answer: The additional protection in the body of aerobic organisms are that they can fight with the ROS radicle formed in the body.
Explanation:
The aerobic organism use oxygen as a final electron acceptor. The aerobic organisms have enzymes in the body which helps in getting from the reactive oxygen species. These enzymes are superoxide dismutase, peroxidase and catalase.
Anaerobes are vulnerable to these ROS which is produced by their own metabolism. They do not contain the enzymes such as superoxide dismutase and catalase that can help them to survive in these conditions.
Hence, because of antioxidants the aerobic organism can survive in oxygen and anaerobes cannot.
