It depends on the process.
Like for example if the process is isothermal(temperature is constant), you can use,
PV = constant or P1V1 = P2V2 where P1V1 are initial conditions and P2V2 are final.
For adiabatic process,
PV^gamma = constant or P1V1 ^gamma = P2V2 ^gamma.
where gamma = Cp
------
Cv
Cp = specific heat at constant pressure and Cv = specific at constant volume.
Value of Gamma will be given in question.
Hope this helps!
Answer:
4.76×10¯⁵ cm
Explanation:
We'll begin by converting 476 nm to m. This can be obtained as follow:
1 nm = 1×10¯⁹ m
Therefore,
476 nm = 476 nm × 1×10¯⁹ m / 1 nm
476 nm = 4.76×10¯⁷ m
Finally, we shall convert 4.76×10¯⁷ m to cm. This can be obtained as follow:
1 m = 100 cm
Therefore,
4.76×10¯⁷ m = 4.76×10¯⁷ m × 100 cm / 1 m
4.76×10¯⁷ m = 4.76×10¯⁵ cm
Thus,
476 nm = 4.76×10¯⁵ cm
Answer:
They have properties of both metals and nonmetals
Explanation:
- Elements in the periodic table may be divided into Metals, non-metals, and metalloids.
- Metals are the elements that react by losing electrons to form stable positively charged ions known as cations. Examples are group 1, 2, and 3 elements together with transition elements.
- Non-metals are those elements that react by gaining electrons to form stable negatively charged ions called anions. Examples include oxygen, carbon, sulfur, etc.
- Metalloids, on the other hand, are elements that have both metallic and non-metallic properties.
- Metalloids occur between metals and non-metals in the periodic table. Examples include Boron and silicon among others.
Answer:
please mark as brainliest!!
Explanation:
ans: gas
The same number of particles in a gas spread further apart than in the liquid or solid states. The same mass takes up a bigger volume . This means the gas is less dense. Density also depends on the material.
Answer:
The reaction in this experiment is termed an iodine clock reaction, because it is the molecular iodine (I2) that undergoes the sudden concentration change. When the iodine concentration increases, it reacts with the starch in the solution to form a complex, turning it a deep blue-black color.
