Answer: I am confident the answer is B
Explanation:
forgive me if im wrong
Two changes would make this reaction reactant-favored
C. Increasing the temperature
D. Reducing the pressure
<h3>Further explanation</h3>
Given
Reaction
2H₂ + O₂ ⇒ 2H₂0 + energy
Required
Two changes would make this reaction reactant-favored
Solution
The formation of H₂O is an exothermic reaction (releases heat)
If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)
While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient
in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2
As the temperature rises, the equilibrium will shift towards the endothermic reaction, so the reaction shifts to the left towards H₂ + O₂( reactant-favored)
And reducing the pressure, then the reaction shifts to the left H₂ + O₂( reactant-favored)⇒the number of coefficients is greater
Atomic number shows the number of protons in an atom's nucleus. If the atomic number is 30, then it has 30 protons. The question says it is neutral, so it must have the same amount of protons and electrons.
A is the correct answer based on this.
Ethyne also known as Acetylene and is the simplest Alkyne belonging to Unsaturated Hydrocarbons. It contains triple bond between two carbon atoms in a molecule. Carbon atoms in Acetylene are sp Hybridized and has a linear shape with bond angle of 180° is present between C-C-H bonds. This compound is also called as Binary Compound because it is made up of two elements i.e. Carbon and Hydrogen. The terminal Hydrogen in Acetylene is slightly Acidic in nature, and this compound can donate terminal proton to any strong base. These compounds generally give Electrophillic Addition Reactions.
