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Artyom0805 [142]

3 years ago

13

Can someone turn 2.785 into a simplified fraction

1 answer:

alexgriva [62]3 years ago

8 0

2 3/4 is the simplified fraction form

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Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.

Masja [62]

Answer:

Step-by-step explanation:

look this solution

5 0

3 years ago

Read 2 more answers

In a group of 60 students, 12 students take Algebra I, 18 students take Algebra II, and 8 students take both subjects. How many

vodomira [7]

Since 8 students take both, that leaves only 4 students who take Algebra I alone.
Likewise since 8 students take both, that leaves 10 who only take Algebra 2
So out of the 60, twenty two are taking either Alg I Alg Ii or both.

That leaves 38 people who are not taking either.
b. 38

You can set this up using a 2 circle venn diagram. Just be sure to put the 8 who take both in first.

4 0

3 years ago

Read 2 more answers

My Than purchased a bicycle costing RS 56oo from a dealer at 51 discount and a sold a profit of 10%. If he had soll it at sy dis

Alisiya [41]

Answer:

sp of bicycle =5600

cp of bicycle =10

now,

profit(p)=sp-cp

=5600-10

=5,590

The profit of bicycle is Rs 5,599

3 0

3 years ago

Which of the choices below is not a possible correlation coefficient?

fiasKO [112]

Answer:

The condition for r is the following:

$-1 \leq r \leq 1$

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

Step-by-step explanation:

The correlation coefficient is a measure of dispersion and is a value between -1 and 1, and is defined as:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

The condition for r is the following:

$-1 \leq r \leq 1$

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

8 0

3 years ago

Which number line represtents the solution to |x+4|=2?

vlada-n [284]

Answer:

Points -2 and -6 on the number line are the two solutions.

Step-by-step explanation:

Use the definition of absolute value as a starting point

$|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x$

To solve the equation, you need to treat the two cases as above:

$|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2$

The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:

$|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x$

Again, the second solution -6 complies with the requirement that x<-4, so it is valid.

7 0

3 years ago