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Monica [59]
4 years ago
13

Please look at this and help me also look at my other question please

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
4 0
\dfrac{3}{7} \div  \dfrac{2}{3} =  \dfrac{3}{7} \times  \dfrac{3}{2} =  \dfrac{9}{14}

1.2 \div 0.04 = 1 \dfrac{2}{10} \div  \dfrac{4}{100}  =  \dfrac{12}{10} \div  \dfrac{4}{100}   =  \dfrac{12}{10} \times  \dfrac{100}{4} = \dfrac{3}{1} \times  \dfrac{10}{1} = 30

8^\frac{2}{3} \div 4^ \frac{1}{2} =   2^{3 \times \frac{2}{3}} \div 2^{2\times \frac{1}{2} } =  2^2 \div 2^1 = 2^{2-1}  = 2
You might be interested in
Betty has $33 to buy plants for her greenhouse. Each plant costs $8. How
meriva

Answer:

4 plants

Step-by-step explanation:

If betty has $33 dollars and each plant is $8, than 33/8 ≈ 4

(8 * 4 is 32)

She will have one dollar left but she can't buy another plant since that's not enough.

3 0
3 years ago
Read 2 more answers
A triangle has an angle that measures 95°. The other two angles are in a ratio of 3:14. What are the measures of those two angle
Marta_Voda [28]

Answer: 15° and 70°

Step-by-step explanation:

The sum of angles of a triangle is 180.

One of the angle is given to be 95°, this means that the sum of the remaining two angles will be ;

180 - 95 =  85°

The ratio of the two sides is given to be 3 : 14

Calculating the angles of each ,the angle with the ratio 3 will be

3/17 x 85 = 15°

The angle with the ratio 14 will be

14/17 x 85 = 70°

Therefore : the measures of the two angles are : 15° and 70°

7 0
3 years ago
Use the Distributive property to rewrite each algebraic Expression (8 +r)4, 8(x+9),
soldi70 [24.7K]

Answer:

(8+r)4

32+4r

8(x+9)

8x+ 72

Step-by-step explanation:

4 0
4 years ago
Help me pleaseeeeee!!!
Svetlanka [38]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\tan(x)  =  \frac{12}{29}  \\

\tan(x)  = 0.413

x≈ 22.475

x ≈22.5

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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